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melisa1 [442]
3 years ago
9

Any of these will help???? Please help me

Mathematics
1 answer:
alexandr402 [8]3 years ago
6 0
1= 70
2= 320
3= 50

I can't do the others I'm sorry but I hope that I helped
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PLEASE HELP ASAP!!!!!!
maksim [4K]
6) 1.6 x 10^-4 = 0.00016
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4 years ago
Simplify the expression 2 (2 + 4y) + 3x.<br> PLS ANSWER ASAP DUE 9:20
Novay_Z [31]

Answer:

5x+8y

Step-by-step explanation:

We can first open the brackets by using the distrubitive propety.

2(x+4y)+3x

2x+8y+3x

Now we can combine like terms.

5x+8y.

I combined the 3x and the 2x. This works because imagined I have 3 of something then I got 2 more of that something I would now have 5 of that something.

Hoped this helped,

JoeLouis2

7 0
3 years ago
3 over 25 as a percent
Bond [772]
It is 12%. This is because if you divide 3 into 25, you get 0.12. In conclusion, it would be 12%.
4 0
4 years ago
Read 2 more answers
Identify the quotient in the form a + bi. HELP ASAP PLEASE!!
Artist 52 [7]

Solving \frac{4-5i}{2+3i} we get -\frac{7}{13}-\frac{22i}{13}

Option A is correct.

Step-by-step explanation:

We need to find the result of \frac{4-5i}{2+3i}

We need to remove i from the denominator. For removing i Multiplying and dividing by 2-3i:

\frac{4-5i}{2+3i}*\frac{2-3i}{2-3i}

Solving:

=\frac{4-5i*2-3i}{2+3i*2-3i}\\=\frac{4(2-3i)-5i*(2-3i)}{(2)^2-(3i)^2}\\=\frac{8-12i-10i+15i^2)}{4-9i^2}\\We\,\,i^2=-1\\=\frac{8-12i-10i+15(-1))}{4-9(-1)}\\=\frac{8-12i-10i-15}{4+9}\\=\frac{8-15-12i-10i}{13}\\=\frac{-7-22i}{13}\\=-\frac{7}{13}-\frac{22i}{13}

So, solving \frac{4-5i}{2+3i} we get -\frac{7}{13}-\frac{22i}{13}

Option A is correct.

Keywords: Complex numbers

Learn more about Complex numbers at:

  • brainly.com/question/10736268
  • brainly.com/question/4678474

#learnwithBrainly

5 0
3 years ago
Zoe and Hannah share tips in the ratio 3:7. Last week Zoe recieved £24. How much did Hannah recieve last week?
Mrrafil [7]
Zoe to Hannah is 3 to 7.
We want to know x.
24 to x
three goes into 24 eight times so multiply 7 by eight
x=56
5 0
3 years ago
Read 2 more answers
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