All categories

2 years ago

Given f(x) = -6x - 1 and g(x) = x3, choose the expression for fºg)(x).

Mathematics

1 answer:

Gelneren [198K]2 years ago

4 0

Answer:

- 6x³ - 1

Step-by-step explanation:

Substitute x = g(x) into f(x), that is

(f ￮ g)(x)

= f(x³ )

= - 6(x³) - 1

= - 6x³ - 1

You might be interested in

Which function below has the lowest y intercept? f(x) graph going through (0, 5) and (2, 1) g(x) Kyle started the summer having

mr Goodwill [35]

First find the slope of f(x).

m=(y2-y1)/(x2-x1)

m=(1-5)/(2-0)

m=-4/2

m=-2

y=-2x+b, using (2,1) we can solve for the y-intercept, "b"

1=-2(2)+b

1=-4+b

5=b

y=-2x+5

So f(x) has a y-intercept of 5

g(x)=6m+3

So g(x) has a y-intercept of 3

h(x)=3x+4

So h(x) has a y-intercept of 4

Then g(x) has the lowest y-intercept of just 3.

6 0

3 years ago

Read 2 more answers

Jon earns $180 per week for each sale. Write an inequality to represents how many sales he needs to make to earn at least $500.

Elenna [48]

The answer is 420 :)

7 0

2 years ago

780 as a percentage of 1.5

Anna [14]

780 as a percentage of 1.5
= $\frac{780}{1.5} *100$
=52,000 percent of 1.5

4 0

2 years ago

A bag contains blue and yellow marbles. Two marbles are drawn without replacement. The probability of selecting a blue marble an

exis [7]

blue marbles
y = yellow marbles
Sum = b+y
The <span>chance of a blue marble being drawn first is:
b / (b+y) = 0.55
</span>The <span>chance of a blue marble being drawn first then a yellow next is:
</span>b / (b+y) * y / (b+y-1) = 0.37
This can be solve easily by using a theorem of Bayes
0.37/0.55 = .67 or 67%

7 0

3 years ago

In a survey of adults who follow more than one sport, 30% listed football as their favorite sport. You survey 15 adults who foll

maxonik [38]

Answer: 0.5

Step-by-step explanation:

Binomial probability formula :-

$P(x)=^nC_x\ p^x(q)^{n-x}$ , where P(x) is the probability of getting success in x trials , n is the total trials and p is the probability of getting success in each trial.

Given : The probability that the adults follow more than one game = 0.30

Then , q= 1-p = 1-0.30=0.70

The number of adults surveyed : n= 15

Let X be represents the adults who follow more than one sport.

Then , the probability that fewer than 4 of them will say that football is their favorite sport,

$P(X\leq4)=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)\\\\=^{15}C_{0}\ (0.30)^0(0.70)^{15}+^{15}C_{1}\ (0.30)^1(0.70)^{14}+^{15}C_{2}\ (0.30)^2(0.70)^{13}+^{15}C_{3}\ (0.30)^3(0.70)^{12}+^{15}C_{4}\ (0.30)^4(0.70)^{11}\\\\=(0.30)^0(0.70)^{15}+15(0.30)^1(0.70)^{14}+105(0.30)^2(0.70)^{13}+455(0.30)^3(0.70)^{12}+1365(0.30)^4(0.70)^{11}\\\\=0.515491059227\approx0.5$

Hence, the probability rounded to the nearest tenth that fewer than 4 of them will say that football is their favorite sport =0.5

4 0

3 years ago