Answer: Not possible to find average amu with only the information provided.
Explanation:
Is there more information about the other isotopes? I don't see how one could calculate an overall atomic mass with only one isotope is known. An isotope of 186.956 with abundance of 62.6% isn't enough information. We're not told anything about the other isotopes: are they larger, smaller, and at what percentage. If one has an amu of 204.956 at 37.4%, the overall atomic mass would be quite different than if it had an atomic mass of 182.956 at 37.4%. More infornmation is required.
Answer:
The initial temperature is 300 K (The temperature doesn't change)
Explanation:
Step 1: Data given
Initial volume = 21L
Final volume = 14L
Initial pressure = 100 kPa = 0.986923 atm
Final pressure = 150 kPa = 1.48038 atm
The final temperature = 300K
Step 2: Calculate the initial temperature
Calculate the initial temperature
(P1*V1)/T1 = (P2*V2)/T2
⇒with P1 = the initial pressure = 0.986923 atm
⇒with V1 = the initial volume = 21 L
⇒ with T1 = the initial temperature = ?
⇒with P2 = the final pressure = 1.48038 atm
⇒with V2 = the final volume = 14 L
⇒with T2 = the final temperature = 300 K
(0.986923 * 21)/T1 = (1.48038*14)/300
T1 = 300 K
The initial temperature is 300 K (The temperature doesn't change)
Answer: kinetic energy
Explanation: I just took that test
Answer:
The three major types of intermolecular interactions are dipole–dipole interactions, London dispersion forces (these two are often referred to collectively as van der Waals forces), and hydrogen bonds.
C.
They broke down mixtures by chemical means.