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blondinia [14]
2 years ago
13

PLZZ HELP ITS TIMED

Chemistry
1 answer:
BartSMP [9]2 years ago
3 0

Answer:Carbon dioxide

Explanation:Carbon dioxide molecules are heavier than air. Because of this, they push the oxygen and other molecules in the air out of the way as they sink down over the flame and candle. When oxygen is pushed away from the wick, it can’t react with the wax anymore. This makes the flame go out.

Next time you blow out a candle, think about what your breath is doing. Why do you think blowing on a candle flame makes it go out?

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CH4(g) + H2O(g) CO(g) + 3H2(g)
boyakko [2]
Presuming the arrow is between H20 and CO

On the left there are 2 gas moles.
On the right there are 4 gas moles.

The equilibrium will shift to the side with the most no. He gas moles when pressure is decreased.

Therefore the answer is A, since 4>2.

If you have any questions, feel free to ask
5 0
3 years ago
What type of chemical bond is formed between two atoms of bromine
MatroZZZ [7]

4 covalent ---because bromine is a non-metal and each atom must share electrons in order to satisfy the octet rule. In a covalent bond, two atoms share a pair of electrons. IOnic bonds form as a result of the transfer of electrons from one atom to another.

6 0
3 years ago
Read 2 more answers
What is the size of a popped balloon
Makovka662 [10]
9,000 meters
Because density is altered by altitude, the helium balloon can reach a height of 9,000 meters, or 29,537 feet. Anything higher than this altitude will cause the helium within the balloon to expand and the balloon to pop.
3 0
3 years ago
Which formula correctly represents the composition of iron III oxide
nikitadnepr [17]
The answer to the question is- Fe2O3
6 0
3 years ago
Calculate Δ H o for the reaction. CH3OH + HCl → CH3Cl + H2O answer is in kJ/mol .
Nimfa-mama [501]

Answer:

\Delta H=-28.08 \frac{kJ}{mol}

Explanation:

Hello,

This types of reactions are likely to be carried out in gaseous phase as it is easier to induce reactions, therefore, for us to compute the change in the enthalpy of this reaction we should write the formation enthalpy of gaseous methanol, hydrogen chloride, methyl chloride and water as -205.1, -92.3, -83.68 and -241.8 kJ/mol respectively. Then, the reaction enthalpy for this reaction is:

\Delta H=\Delta _fH_{CH_3Cl}+\Delta _fH_{H_2O}-\Delta _fH_{CH_3OH}-\Delta _fH_{HCl}\\\\\Delta H=-83.68\frac{kJ}{mol}-241.8\frac{kJ}{mol}-(-205.1\frac{kJ}{mol})-(-92.3\frac{kJ}{mol} )\\\\\Delta H=-28.08 \frac{kJ}{mol}

Which accounts for an exothermic chemical reaction.

Regards.

7 0
4 years ago
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