The solutions of the quadratic equation x² - 5x - 36 = 0 are -4 and 9.
The graph is attached below.
- We are given a quadratic function.
- A polynomial equation of degree two in one variable is a quadratic equation.
- The function given to us is :
- y = x² - 5x - 36
- We need to find the solution of the quadratic function.
- To find the roots, let y = 0.
- x² - 5x - 36 = 0
- Use the quadratic formula.
- In elementary algebra, the quadratic formula is a formula that gives the solution(s) to a quadratic equation.
- x = [-b±√b²-4ac]/2a
- x = [-(-5) ± √25 - 4(1)(-36)]/2(1)
- x = (5 ± √25 + 144)/2
- x = (5 ± √169)/2
- x = (5 ± 13)/2
- x = 9 or x = -4
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Answer:
10
Step-by-step explanation:
3c - 5 =2c +5
3c - 2c =5 +5
c=10
This is an EXPONENT.
To do this all we need to do is multiply the base by itself how many times the power says.
(-6)² = (-6) × (-6) = 36
Recall that any negative number times another negative number is positive so that is why this would be positive.
So, (-6)² = 36
Hope I helped ya!!
We have been given that a right △ABC is inscribed in circle k(O, r).
m∠C = 90°, AC = 18 cm, m∠B = 30°. We are asked to find the radius of the circle.
First of all, we will draw a diagram that represent the given scenario.
We can see from the attached file that AB is diameter of circle O and it a hypotenuse of triangle ABC.
We will use sine to find side AB.
Wee know that radius is half the diameter, so radius of given circle would be half of the 36 that is 
.
Therefore, the radius of given circle would be 18 cm.
