Limit

Mathematics

1 answer:

STatiana [176]3 years ago

5 0

Rationalize the numerator:

$\dfrac{\sqrt{x+4}-2}x\cdot\dfrac{\sqrt{x+4}+2}{\sqrt{x+4}+2}=\dfrac{(\sqrt{x+4})^2-2^2}{x(\sqrt{x+4}+2)}=\dfrac x{x(\sqrt{x+4}+2)}=\dfrac1{\sqrt{x+4}+2}$

This is continuous at $x=0$ , so we can evaluate the limit directly by substitution:

$\displaystyle\lim_{x\to0}\frac{\sqrt{x+4}-2}x=\lim_{x\to0}\frac1{\sqrt{x+4}+2}=\frac1{\sqrt4+2}=\frac14$

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What multiplies to be -18 and adds to be -9?

Harrizon [31]

IMPORTANT:
If you're trying to factor a quadratic in Algebra I:
There are no two integers that can solve this problem!
Your quadratic is <em>prime</em>!

If you're trying to solve a quadratic (find x):
The factoring approach will not work for the same reasons listed above.
Try using splitting the middle or the quadratic formula instead.

Here's how you would solve it from a more advanced approach.
If you don't know what this stuff is, just ignore it.
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(-9-b)b = -18
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Multiply everything by -1 to get rid of all these negative signs.
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Bring over that 18.
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Apply the quadratic formula.
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If you need to write two distinct numbers, just write out one with a + and one with a - in place of the plus-minus sign.

8 0

3 years ago

I feel like being nice, first two answers will get 50 points, the first one to answer gets the brainliest.. (You can put any ans

garik1379 [7]

Answer:

you are so so nice, to give away such big points...may God bless you and stay home and be safe :)

Step-by-step explanation:

1 x 1 is obviously 1

any number multiplied by one that answers that number is the same number.

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<h3>What are helping verbs?</h3>

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brainly.com/question/14061315

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