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3 years ago

Find the slope of the line.

Mathematics

1 answer:

OleMash [197]3 years ago

5 0

Answer:

-30 is the correct answer

Step-by-step explanation:

As we know,

Slope(m) = y2 - y1 / x2 - x1

After calculating we get the answer -30.

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43 is a complement of 24, and m23 = 46, Find m24.

natka813 [3]

Answer:

something

Step-by-step explanation:

7 0

3 years ago

You need to invest $1000 in a bank account and are give two options. The first option is to earn $50 every month you leave the m

garri49 [273]

Answer:

<h3><u>Option 1</u></h3>

Earn $50 every month.

Let x = number of months the money is left in the account
Let y = the amount in the account
Initial amount = $1,000

$\implies y = 50x + 1000$

This is a <u>linear function</u>.

<h3><u>Option 2</u></h3>

Earn 3% interest each month.

(Assuming the interest earned each month is <u>compounding interest</u>.)

Let x = number of months the money is left in the account
Let y = the amount in the account
Initial amount = $1,000

$\implies y = 1000(1.03)^x$

This is an <u>exponential function</u>.

<h3><u>Table of values</u></h3>

<u />

$\large \begin{array}{| c | l | l |}\cline{1-3} & \multicolumn{2}{|c|}{\sf Account\:Balance} \\ \cline{1-3} & \sf Option\:1 & \sf Option\:2 \\\sf Month & \sf \$50\:per\:mth & \sf 3\%\:per\:mth \\\cline{1-3} 0 & \$1000 & \$1000 \\\cline{1-3} 1 & \$1050 & \$1030 \\\cline{1-3} 2 & \$1100 & \$1060.90 \\\cline{1-3} 3 & \$1150 & \$1092.73 \\\cline{1-3} 4 & \$1200 & \$1125.51 \\\cline{1-3} 5 & \$1250 & \$1159.27 \\\cline{1-3} 6 & \$1300 & \$1194.05 \\\cline{1-3} 7 & \$1350 & \$1229.87 \\\cline{1-3}\end{array}$

From the table of values, it appears that <u>Account Option 1</u> is the best choice, as the accumulative growth of this account is higher than the other account option.

However, there will be a point in time when Account Option 2 starts accruing more than Account Option 2 each month. To find this, graph the two functions and find the <u>point of intersection</u>.

From the attached graph, Account Option 1 accrues more until month 32. From month 33, Account Option 2 accrues more in the account.

<h3><u>Conclusion</u></h3>

If the money is going to be invested for less than 33 months then Account Option 1 is the better choice. However, if the money is going to be invested for 33 months or more, then Account Option 2 is the better choice.

3 0

1 year ago

Answer these please!!!!!

garik1379 [7]

4.
-3/4 - 2/3 ÷ (-4/5)
= -3/4 - [2/3 ÷ (-4/5)]
{switch the numerator and denominator when changing from ÷ to ×, or × to ÷}
= -3/4 - [2/3 × (-5/4)]
{numerator × numerator, and denominator × denominator}
= -3/4 - [-10/12]
= -3/4 + 10/12
= -9/12 + 10/12
= 1/12

5.
-2 2/5 + (-2 4/5) × 4/7
= -2 2/5 - (2 4/5 × 4/7)
= -12/5 - (14/5 × 4/7)
= -12/5 - (56/35)
{Simplify fraction to make denominators same}
= -12/5 - (8/5)
= -20/5
= -4/1
= -4

6.
-(-3/5) - 1 3/7 ÷ (-5/14)
{Negative signs cancelled out, fractions compounded}
= 3/5 - 10/7 ÷ (-5/14)
{Switch numerator and denominator when switch from ÷ to ×}
= 3/5 - [10/7 × (-14/5)]
= 3/5 - [-140/35]
= 3/5 + 20/5
= 23/5
{Simplify fraction}
= 4 3/5

Hope this helps! :) You may ask me for more help if you need

3 0

3 years ago

You are helping your older sibling look for an apartment. There are 2 final choices. Apartment A is $1200 per month and requires

kogti [31]

Answer:

20 months.

Step-by-step explanation:

Let the number of months be represented as x

Apartment A is $1200 per month and requires a security deposit of $1000.

= $1200 × x + $1000

1200x + 1000

Apartment B is $1175 per month and requires a security deposit of $1500.

= $1175 × x +$1500

1175x + 1500

Apartment A = Apartment B

1200x + 1000 = 1175x + 1500

Collect like terms

1200x - 1175x = 1500 - 1000

= 25x = 500

x = 500/25

x = 20

Therefore, the costs for both apartment A and B will be the same after 20 months.

6 0

3 years ago

Write 3.01 (the one repeating) as a mixed number in simplest form.

Harrizon [31]

3 1/100

anything before the dot is considered your whole number and anything after the dot is your fraction

6 0

3 years ago