So since the vertex falls onto the axis of symmetry, we can just solve for that to get the x-coordinate of both equations. The equation for the axis of symmetry is 
, with b = x coefficient and a = x^2 coefficient. Our equations can be solved as such:
y = 2x^2 − 4x + 12: 
y = 4x^2 + 8x + 3: 
In short, the vertex x-coordinate's of y = 2x^2 − 4x + 12 is 1 while the vertex's x-coordinate of y = 4x^2 + 8x + 3 is -1.
<h2>Given :-</h2>
In □PQRS side PQ∥ side RS. If m∠P = 108degree
and m∠R = 53degree
<h2>To Find :-</h2>
m∠Q and m∠S.
<h2>Solution :-</h2>
According to angle sum property
P∠Q=180−∠P
∠Q=180−108
For angle S
∠S=180−∠R
∠S=180−53
the answer is A couse divide all 5
Answer:
10 cups of beans to 4 cups of carrots
Step-by-step explanation:
Answer:
x = 4
Step-by-step explanation:
y = - 2 is the equation of a horizontal line parallel to the x- axis.
A perpendicular line is therefore a vertical line parallel to the y- axis with equation
x = c
where c is the value of the x- coordinates the line passes through.
The line passes through (4, - 2 ) with x- coordinate 4 , thus
x = 4 ← equation of perpendicular line
