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Alenkasestr [34]
3 years ago
15

Find the area of the shaded region. Please Help me !!!!

Mathematics
1 answer:
stepan [7]3 years ago
4 0

Answer:

5x^2 + 7x -26

Step-by-step explanation:

multiply to find both areas of both squares. then subtract the smaller area from the larger

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qwelly [4]

Answer:D)

Step-by-step explanation:

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3 years ago
A fraction with a numerator that is greater than or equal to the denominator is an
GarryVolchara [31]
****Equal to one or greater than 1***
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3 years ago
Luetta is shopping and find a $200 video game that is mark down by 5% how much will be taken off the price in dollars
viva [34]

Answer:

$10.00

Step-by-step explanation:

$200 x . 05 = $10.00

5 0
3 years ago
Read 2 more answers
What is the length of LINE GH?<br> And please explain why thank you:
lesya692 [45]

co-ordinates of point G are (1,2)

co-ordinates of point H are (3,-3)

so, by distance formula :

\sqrt{( {x1 - x1})^{2} + ( {y1 - y2})^{2}  }  \\  =  \sqrt{( {1- 3})^{2} + ( {2 - ( - 3)})^{2}  }  \\   \sqrt{( { - 2})^{2} + ( {2  + 3})^{2}  }  \\  \sqrt{( { - 2})^{2} + ( {5})^{2}  }  \\   \sqrt{4 + 25}  \\  \sqrt{29}

so, it is root(29) or 5.38 units

7 0
3 years ago
In 1992, the countries Chad and Denmark each had population of about 5.2 million. However,
irinina [24]

9514 1404 393

Answer:

  5,339,479

Step-by-step explanation:

The populations in millions of the different countries can be represented by the equations ...

  c = 5.2(1.025^t)

  d = 5.2(1.001^t)

We want to find d when c = 10. Solving for t when c=10, we have ...

  10 = 5.2(1.025^t)

  10/5.2 = 1.025^t

  log(10/5.2) = t×log(1.025)

  t = log(10/5.2)/log(1.025)

Then the value of d for that value of t is ...

  d = 5.2(1.001^(log(10/5.2)/log(1.025)) ≈ 5.3394789

The population of Denmark is about 5,339,479 when the population of Chad is 10 million.

_____

If we round the number of years to 26.5 before computing the population of Denmark, we get 5,339,571 -- about 92 more people. Ordinarily, one would not round intermediate results.

3 0
3 years ago
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