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photoshop1234 [79]
3 years ago
10

What is the square root of 16

Mathematics
2 answers:
natima [27]3 years ago
8 0
The\ square\ root\ of\ 16:\\\\\sqrt{16}=4\ because\ 4^2=4\cdot4=16\\--------------------\\de finition\ of\ the\ square\ root:\ \sqrt{a}=b\ if\ b^2=a\ where\ a\geq0\ and\ b\geq0
777dan777 [17]3 years ago
4 0
\sqrt{16} = \sqrt{4\times 4} =  \sqrt{4^2} =4^{\frac {2}{2}} =4^1=4
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To the nearest tenth, find the perimeter of ABC with vertices A (-2,-2) B (0,5) and C (3,1)
Pavlova-9 [17]

the perimeter will then just be the sum of the distances of A, B and C, namely AB + BC + CA.


\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-2})\qquadB(\stackrel{x_2}{0}~,~\stackrel{y_2}{5})\qquad \qquadd = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}\\\\\\AB=\sqrt{[0-(-2)]^2+[5-(-2)]^2}\implies AB=\sqrt{(0+2)^2+(5+2)^2}\\\\\\AB=\sqrt{4+49}\implies \boxed{AB=\sqrt{53}}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\B(\stackrel{x_2}{0}~,~\stackrel{y_2}{5})\qquad C(\stackrel{x_1}{3}~,~\stackrel{y_1}{1})\\\\\\BC=\sqrt{(3-0)^2+(1-5)^2}\implies BC=\sqrt{3^2+(-4)^2}


\bf BC=\sqrt{9+16}\implies \boxed{BC=5}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\C(\stackrel{x_2}{3}~,~\stackrel{y_2}{1})\qquad A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-2})\\\\\\CA=\sqrt{(-2-3)^2+(-2-1)^2}\implies CA=\sqrt{(-5)^2+(-3)^2}\\\\\\CA=\sqrt{25+9}\implies \boxed{CA=\sqrt{34}}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\~\hfill \stackrel{AB+BC+CA}{\approx 18.11}~\hfill

5 0
3 years ago
(6 to the power of 3 times 3 to the power of 3) to the power of 2
frosja888 [35]

Answer:

True

Step-by-step explanation:

(6³ * 3³)² = 18⁶

Multiply inside the parenthesis.

(18³)² = 18⁶

When you put powers to powers, they multiply, eg:

(x³)⁴ = x³°⁴ = x¹²

18⁶ = 18⁶

True.

4 0
2 years ago
according to the fundemental theorem of algebra, how many roots exist for the polynomial function? f(x) = (x^3-3x+1)^2
Svetradugi [14.3K]

Answer:

6

Step-by-step explanation:

First, we can expand the function to get its expanded form and to figure out what degree it is. For a polynomial function with one variable, the degree is the largest exponent value (once fully expanded/simplified) of the entire function that is connected to a variable. For example, x²+1 has a degree of 2, as 2 is the largest exponent value connected to a variable. Similarly, x³+2^5 has a degree of 2 as 5 is not an exponent value connected to a variable.

Expanding, we get

(x³-3x+1)²  = (x³-3x+1)(x³-3x+1)

= x^6 - 3x^4 +x³ - 3x^4 +9x²-3x + x³-3x+1

= x^6 - 6x^4 + 2x³ +9x²-6x + 1

In this function, the largest exponential value connected to the variable, x, is 6. Therefore, this is to the 6th degree. The fundamental theorem of algebra states that a polynomial of degree n has n roots, and as this is of degree 6, this has 6 roots

3 0
3 years ago
HOW DID THEY GET THIS ANSWERR!!! PLZZ HELPPP EXAM SOON
VARVARA [1.3K]

Answer:

Yes . You are correct.

Step-by-step explanation:

(x + 5)^2 + (y + 10)^2 = 81.

3 0
3 years ago
What is 16 trillion in decimal form
JulijaS [17]
16000000000000.
Hope it helped
3 0
3 years ago
Read 2 more answers
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