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3 years ago

What is the square root of 16

2 answers:

8 0

$The\ square\ root\ of\ 16:\\\\\sqrt{16}=4\ because\ 4^2=4\cdot4=16\\--------------------\\de finition\ of\ the\ square\ root:\ \sqrt{a}=b\ if\ b^2=a\ where\ a\geq0\ and\ b\geq0$

777dan777 [17]3 years ago

4 0

$\sqrt{16} = \sqrt{4\times 4} = \sqrt{4^2} =4^{\frac {2}{2}} =4^1=4$

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How do you find the square root of 2809

Hunter-Best [27]

If this is greater than the first part of the number called by the spectator (i.e., ignoring the last two digits), then the last digit of your answer is the lower of the two possible values. Otherwise the last digit is the higher value. For example if the number called is 2809, the square root could be either 53 or 57.

4 0

2 years ago

Read 2 more answers

Which two lines must be parallel in the diagram?

djverab [1.8K]

Answer: j || k

Step-by-step explanation:

only j and k are explicitly shown to be 90 degrees, so they must be parallel since they have the same angle when intersected by line <em>l.</em>

8 0

2 years ago

A ship sails 250km due North qnd then 150km on a bearing of 075°.1)How far North is the ship now? 2)How far East is the ship now

algol [13]

The answers to the bearing problems are listed below:

How far North is the ship now ___________ 38.82 km
How far East is the ship now ____________ 144.89 km
How far is the ship from its starting point_____241.48 km
On what bearing is it now from its original position____035°

<h3>Meaning of bearing.</h3>

Bearing can defined as branch of mathematics that describes the accurate location of an object at any point in time.

<h3>Analysis</h3>

The answers to the problem from 1-3 can be gotten by using sin and cos to find the missing sides.

The final value can be gotten using the cosine rule

4). bearing from original position = $cos^{-1}$ ( $a^{2}$ + $b^{2}$ ﹣ $c^{2}$ ) / $2ab$ = 35°

In conclusion, the answers for each is given in the list above.

Learn more about Bearing: brainly.com/question/24142612

#SPJ1

8 0

1 year ago

Please help! Thanks in advance.

alukav5142 [94]

In this problem, we need to plug in the given x values for $f(x)=0$ and find a and b.

When we plug in 1, we get: $2 \times {1}^{4} - 5 \times {1}^{3} - 14 \times {1}^{2} + a \times 1 + b = 0$

Simplify:
$2 - 5 - 14 + a + b = 0$
$- 17 + a + b = 0$
$a + b = 17$

We got our first statement about the values of the variables. If we find one more we can find those 2 variables.

We have another given root: 4.

Plug it in:
$2 \times {4}^{4} - 5 \times {4}^{3} - 14 \times {4}^{2} + a \times 4 + b = 0$
$512 - 320 - 224 + 4a + b = 0$
$- 32 + 4a + b = 0$
$4a + b = 32$

Now we have our second one. We can combine them:
$a + b = 17 \\ 4a + b = 32$

I use elimination method which is easier here.

Multiply the top equation by -1: $- a - b = - 17 \\ 4a + b = 32$

Add them up:
$3a = 15$

Simplify:
$a = 5$

Now we have a, we can plug in one of those equations to find b:
$5 + b = 17$
$b = 17 - 5$
$b = 12$

So, the answers are $a=5$ and $b=12$ .

6 0

3 years ago

An athlete plains to run 3 miles. Each lap around th school yard is 3/7 miles how many laps will the athlete run

kati45 [8]

Answer: 7 laps

Step-by-step explanation:

The athlete planned to run 3 miles

1 lap = 3/7 miles

x laps = 3 miles

by proportion :

x × 3/7miles = 3 miles

x = 3 ÷ 3/7

x = 3 x 7/3

x = 7

Therefore: the athlete will run 7 laps

3 0

3 years ago