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miv72 [106K]
3 years ago
5

Kelly makes fruit juice each morning. She uses 2 1/3 pints of strawberries and 1 2/5 pints of grapes in her juice. How many more

pints of strawberries then pints of grapes does she use?
Mathematics
1 answer:
Monica [59]3 years ago
6 0
2 1/3 -1 2/5 =1 1/10
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A) 2(x+3)=x-4 <br>Could anyone help?​
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If solving for x you will first need to combine like terms. Then after getting the amount of numbers and amount of x numbers you will divide the x number from both. After doing that you would get X=-10
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You are looking at comparable houses with the same asking prices in neighboring towns. The mill rate in the first town is 20 mil
zalisa [80]
C) is the answer!!!!!!!
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3 years ago
Dante and Mia have a total of 350 pennies in their piggy banks, altogether. After Dante lost half of his pennies and Mia lost on
tatuchka [14]

Answer:

150 pennies were lost altogether

Step-by-step explanation:

Let the initial number of pennies owned by Dante be x pennies

Let the initial number of pennies owned by Mia be y pennies

Mathematically ;

x + y = 350 •••••••(i)

So after losing half, dante will have x/2 pennies left.

Mia lost 1/3 so she will have 2/3y left

So after all the losses, they both had equal amount of pennies

This means that;

x/2 = 2y/3

Cross multiply;

3x = 4y •••••••(ii)

Let’s solve both equations simultaneously;

From i , x = 350-y

Substitute this into equation ii

3(350-y) = 4y

1050-3y = 4y

7y = 1050

y = 1050/7

y = 150

since x = 350-y

x = 350-150 = 200

Now Dante loss x/2 = 200/2 = 100

Mia lost 1/3y = 1/3 * 150 = 50

Total pennies lost = 100 + 50 = 150

7 0
3 years ago
Add me on snap gamerdylan19 insta is reaper_shot and tiki's Tok is death_shot55
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Answer:

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the absolute minimum and absolute maximum values of f on the given interval. f(x) = x − ln 8x, [1/2, 2]
insens350 [35]
The given function is 
f(x) =  x - ln(8x), on the interval [1/2, 2].

The derivative of f is
f'(x) = 1 - 1/x
The second derivative is 
f''(x) = 1/x²

A local maximum or minimum occurs when f'(x) = 0.
That is,
1 - 1/x = 0  => 1/x = 1  => x =1.
When x = 1, f'' = 1 (positive).
Therefore f(x) is minimum when x=1.
The minimum value is
f(1) = 1 - ln(8) = -1.079

The maximum value of f occurs either at x = 1/2 or at x = 2.
f(1/2) = 1/2 - ln(4) = -0.886
f(2)  = 2 - ln(16) = -0.773
The maximum value of f is
f(2) = 2 - ln(16) = -0.773
A graph of f(x) confirms the results.

Answer: 
Minimum value  = 1 - ln(8)
Maximum value = 2 - ln(16)


4 0
3 years ago
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