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garik1379 [7]
3 years ago
6

A local petting zoo allows visitors to feed the goats food pellets. The petting zoo starts the month with 525.25 pounds of food

pellets. Each week, the workers track the amount of food pellets given out and any food pellet deliveries.
Week Change in Food Pellets (lb)
1 −16412
2 −189.75
3 35578
4 −200316

How many pounds of food pellets will the petting zoo have left at the end of the month? Write your answer as a mixed number in simplest form.



__ pound(s)
Mathematics
2 answers:
Alisiya [41]3 years ago
6 0
I’m sorry, I wish I knew this one and I would help
erica [24]3 years ago
4 0

Answer:

it would be -189.75

Step-by-step explanation:

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What is the value of d if the volume of Prism F is 99 cubic units ?
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Answer:

d = 3.46 units

Step-by-step explanation:

The diagram below is a rectangular prism . The volume of the prism is given as  99 units³ .

volume of a rectangular prism = Length × width × height

height = 5.2 units

volume = 99 units³

length = 5.5 units

width = d

let us find the width which is d

volume = L × w × h

99 = 5.5 × d × 5.2

99 = 28.6d

divide both sides by 28.6

d = 99/28.6

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d = 3.46 units

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3 years ago
What is the term used for two equal ratios:
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5 0
3 years ago
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(I WILL GIVE YOU BRAINLIEST AND ANSWER ALL YOU CAN IDC) a market researcher tracks the number of people who visits a company's w
lawyer [7]

Part A: The exponential function is the best model for the given data. The data shows that every month the number of visitor approximately doubles from previous month. In other words the number is some base value (2, in this case) with the number of month (t) being in the exponent. This the a key characteristic of an exponential growth.  

Part B: (also explained above). Every month the number of visitors approximately doubles. Starting with 5.74 at month 8, the numbers goes up by about the same amount to 12.0 at month 9. At month 10, a similar increase occurs (doubling would be 24, and the data shows 25, so this is all "aproximate"). This trend continues throughout the table.

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5 0
3 years ago
5. A survey of student pizza preferences showed that 43 students preferred cheese, 56 preferred sausage, 39 preferred pepperoni,
cestrela7 [59]

Answer:

P (Cheese) = 0.199, P (Sausage) = 0.259, P (Pepperoni) = 0.181,

P (Supreme) = 0.130, P (Another Kind) = 0.144

and P (Does not like any kind) = 0.088

Step-by-step explanation:

Given:

Number of students who prefer cheese = 43

Number of students who prefer sausage = 56

Number of students who prefer pepperoni = 39

Number of students who prefer supreme = 28

Number of students who prefer another kind = 31

Number of students who did not like any kind = 19

∴ The total number of students surveyed = 43+56+39+28+31+19=216       The number of students who prefer pizza = 43+56+39+28+31=197

The probability that a students likes pizza is,

P(Student\ likes\ pizza)=\frac{No.\ of\ students\ who\ prefer\ pizza}{Total\ no.\ of\ students\ surveyed}

                                     =\frac{197}{216} \\=0.912

The probability that a students does not likes pizza is,

P(Student\ does\ not\ likes\ pizza)=\frac{No.\ of\ students\ who\ does\ not\ prefer\ pizza}{Total\ no.\ of\ students\ surveyed}

                                                   =\frac{19}{216} \\=0.088

The probability distribution of students who prefer different kinds of pizza is:

  • The probability that a student likes cheese:

       P(A\ Student\ prefers\ cheese)=\frac{No.\ of\ students\ who\ prefer\ cheese}{Total\ no.\ of\ students\ surveyed}

                                                       =\frac{43}{216}\\=0.199

  • The probability that a student likes sausage:

        P(A\ Student\ prefers\ sausage)=\frac{No.\ of\ students\ who\ prefer\ sausage}{Total\ no.\ of\ students\ surveyed}

                                                           =\frac{56}{216}\\=0.259

  • The probability that a student likes pepperoni:

       P(A\ Student\ prefers\ pepperoni)=\frac{No.\ of\ students\ who\ prefer\ pepperoni}{Total\ no.\ of\ students\ surveyed}  

                                                             =\frac{39}{216}\\=0.181

  • The probability that a student likes supreme:

       P(A\ Student\ prefers\ supreme)=\frac{No.\ of\ students\ who\ prefer\ supreme}{Total\ no.\ of\ students\ surveyed}

                                                           =\frac{28}{216}\\=0.130

  • The probability that a student likes another kind:

        P(A\ Student\ prefers\ another\ kind)=\frac{No.\ of\ students\ who\ prefer\ another\ kind}{Total\ no.\ of\ students\ surveyed}

                                                                   =\frac{31}{216}\\=0.144

Thus, the probability distribution table is displayed below:

6 0
3 years ago
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