Answer:
A. 34,689.370
b.35,000.00
Step-by-step explanation:
(8.6 x 108) x (3.2 x103
place them in order
(8.6 x 3.2) x (108 x 103)
27.52 x (108 x 103)
27.52 x 11124
That is your answer to this question.
Since x = -9, you substitue the X for -9.
your equation would then be y = |-9| +1
|x| is absolute vale and makes everything inside positive.
so really it is y = 9+1
y = 10
Answer:
Perpendicular lines have a slope that is the negative reciprocal of the given line.
For example, if a given line has the slope 3/2, the the perpendicular line would have the slope -2/3.
For the given line: y = 4x - 7, the perpendicular line would have a slope of -1/4
There isn't enough info in the question to determine the y-intercept. Literally, any y-intercept could work and the line would still be perpendicular. Is the line supposed to pass through a certain point?
Your answer would be something like: y = -1/4 x + b
b is the y-intercept...if your question paper is multiple choice, choose the answer with the slope of -1/4. If it's supposed to pass through a certain point (x,y) replace x and y with the values in that point and solve for b to get the y-intercept.
Answer:
The proportion of temperatures that lie within the given limits are 10.24%
Step-by-step explanation:
Solution:-
- Let X be a random variable that denotes the average city temperatures in the month of August.
- The random variable X is normally distributed with parameters:
mean ( u ) = 21.25
standard deviation ( σ ) = 2
- Express the distribution of X:
X ~ Norm ( u , σ^2 )
X ~ Norm ( 21.25 , 2^2 )
- We are to evaluate the proportion of set of temperatures in the month of august that lies between 23.71 degrees Celsius and 26.17 degrees Celsius :
P ( 23.71 < X < 26.17 )
- We will standardize our limits i.e compute the Z-score values:
P ( (x1 - u) / σ < Z < (x2 - u) / σ )
P ( (23.71 - 21.25) / 2 < Z < (26.17 - 21.25) / 2 )
P ( 1.23 < Z < 2.46 ).
- Now use the standard normal distribution tables:
P ( 1.23 < Z < 2.46 ) = 0.1024
- The proportion of temperatures that lie within the given limits are 10.24%
