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sergejj [24]
3 years ago
13

PLEASE ANSWER ASAP!!!!!! CORRECT WILL GET BRAINLIEST!!

Mathematics
1 answer:
Reptile [31]3 years ago
4 0
Is the answer probably going to be a or c? hope that helped
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Please provide steps with answers
Sunny_sXe [5.5K]

Answer:

it's answer is 36 inch ²

Hope it will help as I have my answers with picture.

4 0
3 years ago
Read 2 more answers
What is the sum of 2equal numbers
meriva
Let the number be x
The sum of 2 equal numbers is simply x+x or 2x.
5 0
4 years ago
6. Classify this kind of triangle:
const2013 [10]

Answer:

Number 3

Step-by-step explanation:

It is an acute isosceles because all the angles are acute and two sides are congruent.

7 0
3 years ago
Read 2 more answers
Need Help Fast!!! 10 points!
Aleksandr [31]

EF = 12

Step-by-step explanation:

Step 1 :

The square of side 18 in is divided into 3 parts of equal area by the polygonal chain

So we have

Area of the figure ABCE = Area of the figure AECF = Area of the figure AFCD

Step 2 :

Area of figure ABCE is Area of the triangle AME + Area of the trapezium EMBC

Area of triangle AME = 1/2(ME )(AM) where ME is the base and AM = 9 is the height of the triangle ( AM = 9 since M is the midpoint of AB)

Area of triangle AME = 1/2(ME )9 = 9/2(ME)

Area of the trapezium EMBC = 1/2(ME +BC)(MB) Where ME and BC are the 2  parallel sides and MB is the distance between them

Area of the trapezium EMBC = 1/2(ME+18)9 = 9/2(ME+18)

Therefore

Area of figure ABCE = 9/2(ME) + 9/2(ME+18)

=  9/2(ME +ME+18)

But we know that the area of this figure is 1/3 of the area of the square = 1/3(18*18) = 108

So, 9/2(ME +ME+18) = 108  => 2 ME + 18 = 24 = > ME = 3

Step 3 :

Using the same procedure as above we get, FN = 3

Also we have

ME + EF + FN = 18  ( side of the square)

3 + EF + 3 = 18 => EF = 12

5 0
4 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%7B2%7D%5E%7Bx%7D%20%20%20%2B%203" id="TexFormula1" title="f(x) = {2}^{x} +
lisov135 [29]

The function is given f(x)=2^x+3.

Now let's solve for f(-2).

f(-2)=2^{-2}+3

Rule of negative exponent: x^{-1}=\frac{1}{x^1}.

f(-2)=\frac{1}{2^2}+3

f(-2)=\frac{1}{4}+\frac{3}{1}

Rule for sum of fractions: \frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}.

f(-2)=\frac{13}{4}

And the result is:

f(-2)=\boxed{\frac{13}{4}=3.25}

4 0
3 years ago
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