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2 years ago

Evaluate 82 - 2^3 x5

Mathematics

2 answers:

Anettt [7]2 years ago

6 0

I think the answer is 42.

kkurt [141]2 years ago

6 0

Answer:

the answer would be 42.

Step-by-step explanation:

82 - 2³ × 5

82 - 8 × 5

82 - 40

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mrs_skeptik [129]

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Step-by-step explanation:

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2 years ago

It's a ven dyagram question pls help

slamgirl [31]

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a) A U B = {21,23,24,25,27,29,30,31 }

b) A n C = {24,30}

Step-by-step explanation:

A {21,24,27,30}

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a) A U B = {21,23,24,25,27,29,30,31 }

b) A n C = {24,30}

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2 years ago

How do you find the surface area of a regular pyramid

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3 years ago

(solve the literal equation for y ). <br> 1.) 8x + 2y = 18<br> 2.) 7x - y = 35

nekit [7.7K]

1. Write in y=mx+b Form 8x+2y=18. 8x+2y=18 8 x + 2 y = 18. The slope-intercept form is y=mx+b y = m x + b , where m m is the slope and b b is the y-intercept.

2. Simple and best practice solution for 7x-y=35 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand,

4 0

3 years ago

Read 2 more answers

Resolve into partial fractions 7-5x/2x^2+x-1

Flauer [41]

The decomposition of partial fractions is to start with the simplified reply and then take it apart, to "decompose" the final expression into its initial polynomial fractions.

Given:

$\to \bold{\frac{7-5x}{2x^2+x-1}}\\\\$

To find:

partial fractions=?

Solution:

$\to \bold{\frac{7-5x}{2x^2+x-1}}\\\\\to \bold{\frac{7-5x}{2x^2+x(2-1)-1}}\\\\\to \bold{\frac{7-5x}{2x^2+2x-x-1}}\\\\\to \bold{\frac{7-5x}{2x(x+1)-1(x+1)}}\\\\\to \bold{\frac{7-5x}{(2x-1)(x+1)} = \frac{A}{(2x-1)} - \frac{B}{(x+1)} }\\\\\to \bold{7-5x = \frac{A ((2x-1)(x+1))}{(2x-1)} - \frac{B((2x-1)(x+1))}{(x+1)} }\\\\\to \bold{7-5x = A(x+1) -B(2x-1) }\\\\$

putting $x=-1$

$\to \bold{7-5(-1) = A(-1+1) -B(2(-1)-1) }\\\\\to \bold{7+5 = A(0) -B(-2-1) }\\\\\to \bold{12 = +3B }\\\\\to \bold{B = \frac{12}{3} }\\\\\to \bold{B = 4 }\\\\$

putting $x= \frac{1}{2}$

$\to \bold{7-5(\frac{1}{2}) = A(\frac{1}{2}+1) -B(2(\frac{1}{2})-1) }\\\\\to \bold{7-\frac{5}{2} = A(\frac{3}{2}) -B((\frac{2}{2})-1) }\\\\\to \bold{7-\frac{5}{2} = A(\frac{3}{2}) -B(1-1) }\\\\\to \bold{\frac{14-5}{2} = A(\frac{3}{2}) -B(0) }\\\\\to \bold{\frac{9}{2} = A(\frac{3}{2})}\\\\\to \bold{\frac{9}{2} \times \frac{2}{3} = A}\\\\\to \bold{\frac{9}{3} = A}\\\\\to \bold{A=3}\\\\$

So, the final answer is " $\bold{\frac{7-5x}{(2x-1)(x+1)} = \frac{3}{(2x-1)} - \frac{4}{(x+1)} }\\\\$ ".

Learn more:

brainly.com/question/22286068

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3 years ago