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lord [1]
3 years ago
8

Divide. 1,229 ÷ 14 Enter your answer in the boxes as a mixed number in simplest form.

Mathematics
1 answer:
Tatiana [17]3 years ago
3 0

Answer:

87 11/14

Step-by-step explanation:

1,229 ÷ 14

It can also be written as

1,229 / 14

14 in 12 is not possible

14 in 122 is 8 remainder 10

The 10 remaining + 9 in the the given expression

14 in 109 is 7 remainder 11

The answer is 87 11/14

87 whole number 11 over 14

1,229 / 14 = 87 11/14

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Choose all of the transformations that are rigid motions.
kkurt [141]

Answer:

The answer is below

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, dilation and rotation.

Rigid transformations are transformation that produces an image with the same size, shape and angle as the original object. Rigid transformations are translation, rotation and reflection.

Dilation is not a rigid transformation.

All the transformations attached are rigid transformations.

7 0
3 years ago
6x -2x3 + 10x+2x3+7x4 simply
zmey [24]
(((6x-(2*(x3)))+10x)+(2*(x3)))+7x4 \\ \\ Then \ we \ simplify \ it \ down \ more. \\ \\   (((6x-(2*(x^3)))+10x)+2x^3)+7x^4 \\ \\ then \ we \ would \ then \ pull \ out \ the \ like \ factors . . . . \\ \\  7x^4 + 16x  =   x * (7x^3 + 16) \\ \\

Your final answer: \boxed{\bf{  x *(7x^3 + 16)}}
4 0
3 years ago
Read 2 more answers
Given a mean earth radius of 20,906,000 ft, and an observation latitude of n 42 degrees, what is the arc distance of one second
murzikaleks [220]

Answer:

  • arc second of longitude: 75.322 ft
  • arc second of latitude: 101.355 ft

Explanation:

The circumference of the earth at the given radius is ...

  2π(20,906,000 ft) ≈ 131,356,272 ft

If that circumference represents 360°, as it does for latitude, then we can find the length of an arc-second by dividing by the number of arc-seconds in 360°. That number is ...

  (360°/circle)×(60 min/°)×(60 sec/min) = 1,296,000 sec/circle

Then one arc-second is

  (131,356,272 ft/circle)/(1,296,000 sec/circle) = 101.355 ft/arc-second

__

Each degree of latitude has the same spacing as every other degree of latitude everywhere. So, this distance is the length of one arc-second of latitude: 101.355 ft.

_____

<em>Comment on these distance measures</em>

We consider the Earth to have a spherical shape for this problem. It is worth noting that the measure of one degree of latitude is almost exactly 1 nautical mile--an easy relationship to remember.

3 0
3 years ago
Gina is training for a marathon. She ran 4.6 miles on Friday and 6.75 miles on Saturday. On Sunday, she ran 13 miles. How much f
navik [9.2K]

Answer:

1.65

Step-by-step explanation:

First you need to find the sun of 4.6 and 6.75, you should do this because it is asking for the two numbers combined. When you add these two numbers, you get 11.35

Now you need to subtract 13 and 11.35 because it wants to know how much father she ran on Saturday than friday, signaling subtraction. When you subtract 13-11.35 you should get 1.65

4 0
3 years ago
1 point
Anton [14]

Answer:

  C.  350 miles

Step-by-step explanation:

Daphne wants to drive 3/4 of the distance in the first 2 days. So, her mileage per day should be about (3/4)/2 = 3/8 of the total mileage:

  (3/8)(932.4 mi) = 349.65 mi ≈ 350 mi

She should drive about 350 miles on each of the first 2 days.

8 0
3 years ago
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