Ask question

Ask question

All categories

3 years ago

8

The base of a cube is 1/4 ft squared. Whats the volume of the cube? also can you explain your answer so i can answer other quest

ions like it, thanks!!

2 answers:

MrMuchimi3 years ago

8 0

It would be 1/64 I hope this helps with your question.

Mama L [17]3 years ago

8 0

The answer is 1/64 i believe

You might be interested in

What is 2/3x + 1/4x= 6 ??????

erik [133]

Use Cymath to find your answer

8 0

3 years ago

Read 2 more answers

8. Simplify 7a + 5b + 301 - 2b

Kay [80]

Step-by-step explanation:

7a+5b+301 should be simplify

6 0

3 years ago

Read 2 more answers

In the U.S. we consume 20 million barrels of oil per day. If the U.S. population is 320 million people, how many barrels per day

anyanavicka [17]

Answer:

1/16 or 0.0625

Step-by-step explanation:

Divide 20 by 320 and you get 1/16 or 0.0625

6 0

3 years ago

When a bactericide is added to a nutrient broth in which bacteria are growing, the bacteria population continues to grow for a

baherus [9]

Answer:

a) 1296 bacteria per hour

b) 0 bacteria per hour

c) -1296 bacteria per hour

Step-by-step explanation:

We are given the following information in the question:

The size of the population at time t is given by:

$b(t) = 9^6 + 6^4t-6^3t^2$

We differentiate the given function.

Thus, the growth rate is given by:

$\displaystyle\frac{db(t)}{dt} = \frac{d}{dt}(9^6 + 6^4t-6^3t^2)\\\\= 6^4-2(6^3)t$

a) Growth rates at t = 0 hours

$\displaystyle\frac{db(t)}{dt} \bigg|_{t=0}= 6^4-2(6^3)(0) = 1296\text{ bacteria per hour}$

b) Growth rates at t = 3 hours

$\displaystyle\frac{db(t)}{dt} \bigg|_{t=3}= 6^4-2(6^3)(3) = 0\text{ bacteria per hour}$

c) Growth rates at t = 6 hours

$\displaystyle\frac{db(t)}{dt} \bigg|_{t=6}= 6^4-2(6^3)(6) = -1296\text{ bacteria per hour}$

3 0

4 years ago

I need the answers for this

velikii [3]

Answer:

q1 9.2

q2 5.9

q3 8.4

Q4 7.5

q5 7.3

q6 5.1

5 0

3 years ago