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Arlecino [84]
3 years ago
7

The mean one-way commute to work in Chowchilla is 7 minutes. The standard deviation is 2.4 minutes, and the population is normal

ly distributed. What is the probability of randomly selecting one commute time and finding that: a). P (x < 2 mins) _____________________________ b). P (2 < x < 11 mins) _____________________________ c). P (x < 11 mins) ________________________________ d). P (2 < x < 5 mins) _______________________________ e). P (x > 5 mins)
Mathematics
1 answer:
adell [148]3 years ago
8 0

Answer:

The answer is below

Step-by-step explanation:

Given that:

The mean (μ) one-way commute to work in Chowchilla is 7 minutes. The standard deviation (σ) is 2.4 minutes.

The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

z=\frac{x-\mu}{\sigma}

a) For x < 2:

z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08

From normal distribution table,  P(x < 2) = P(z < -2.08) = 0.0188 = 1.88%

b) For x = 2:

z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08

For x = 11:

z=\frac{x-\mu}{\sigma}=\frac{11-7}{2.4} =1.67

From normal distribution table, P(2 < x < 11) = P(-2.08 < z < 1.67 ) = P(z < 1.67) - P(z < -2.08) = 0.9525 - 0.0188 = 0.9337  

c) For x = 11:

z=\frac{x-\mu}{\sigma}=\frac{11-7}{2.4} =1.67

From normal distribution table,  P(x < 11) = P(z < 1.67) = 0.9525

d) For x = 2:

z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08

For x = 5:

z=\frac{x-\mu}{\sigma}=\frac{5-7}{2.4} =-0.83

From normal distribution table, P(2 < x < 5) = P(-2.08 < z < -0.83 ) = P(z < -0.83) - P(z < -2.08) =  0.2033- 0.0188 = 0.1845  

e) For x = 5:

z=\frac{x-\mu}{\sigma}=\frac{5-7}{2.4} =-0.83

From normal distribution table,  P(x < 5) = P(z < -0.83) = 0.2033

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compará y ordena de mayor a menor las siguientes cantidades 23.4 ,15/20 ,32.245,.056,4/10,50/100,8/9,.009,9/1000 y 54.45​
nignag [31]

Answer:

El orden de mayor a menor es:

54.45 ; 32.245 ; 23.4 ; 8/9 ; 15/20 ; 50/100 ; 4/10 ; 0.056 ; 9/1000

Step-by-step explanation:

El mayor número será el que tenga el mayor entero, o  si tienen el mismo entero será aquel que tenga el primer decimal mayor de izquierda a derecha,  o si tienen el mismo se observa el siguiente decimal y así sucesivamente.

Para ordenar y comparar las cantidades es conveniente en primer lugar pasar todos los números a decimales. Para convertir una fracción en un decimal, debes dividir el numerador entre el denominador.

Entonces, en este caso el valor decimal de cada cantidad (o una aproximación) es:

23.4

15/20= 0.75

32.245

0.056

4/10= 0.4

50/100= 0.5

8/9= 0.8888

0.009

9/1000= 0.009

54.45​

Entonces <u><em>el orden de mayor a menor es: </em></u>

<u><em> 54.45 ; 32.245 ; 23.4 ; 8/9 = 0.8888 ; 15/20 = 0.75 ; 50/100 = 0.5 ; 4/10 = 0.4 ; 0.056 ; 9/1000 = 0.009</em></u>

7 0
2 years ago
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