In space ?? Idk what you mean but I guess it's not possible ?
Answer:
The arrow is at a height of 48 ft after approximately <u>0.55</u> s and after <u>5.45</u> s
Step-by-step explanation:
The following information is missing:
<em>The height of an arrow shot upward can be given by the formula s = v0*t - 16*t², where v0 is the initial velocity and t is time.How long does it take for the arrow to reach a height of 48 ft if it has an initial velocity of 96 ft/s? </em>
If the arrow is at a height of 48 ft and its initial velocity is 96 ft/s, then:
48 = 96*t - 16*t²
16*t² - 96*t + 48 = 0
16*(t² - 6*t + 3) = 0
t² - 6*t + 3 = 0
t² - 6*t + 3 + 6 = 0 + 6
t² - 6*t + 9 = 6
(t - 3)² = 6
t - 3 = √6
t - 3 = 2.45; t = 2.45 + 3; t = 5.45
or
t - 3 = -2.45; t = -2.45 + 3; t = 0.55
Answer:
16800
Step-by-step explanation:
800
* 21
---------
Multiply: 800*1=800
Multiply: 800*2=1600
Add: 16800+800=16800
Answer:
2 + x + y
Step-by-step explanation:
i think it would be 960 feet. bc you would multiply 4 by 60, then multiply 240 by 4.
i think thats how you solve it. hope that helped :)
