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sertanlavr [38]
3 years ago
13

Find x, y, and z.

Mathematics
1 answer:
earnstyle [38]3 years ago
5 0

Answer:

x=4.5,y=5,z=9

Step-by-step explanation:

First, we use the pythagorean theorem in the lower right triangle (with sides 4,x,6) and find x^2+4^2=6^2 and therefore x^2=6^2-4^2=20 so x=√20 which is approximately 4.5.

Also, we can see from the picture that z=y+4, and therefore the only option left is x=4.5,y=5,z=9.

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Answer:

Step-by-step explanation:

Frequency table for the height of the seedlings,

Height (in inches)        Number of seedlings

          \frac{1}{2}                                      2              

          \frac{3}{4}                                      4

          \frac{5}{8}                                      2

          \frac{7}{8}                                      2

Now we can draw the line plot as attached.

Average height of the seedlings = \frac{2(\frac{1}{2})+4(\frac{3}{4})+2(\frac{5}{8})+2(\frac{7}{8})}{2+4+2+2}

                                                      = \frac{1+3+1.25+1.75}{10}

                                                      = \frac{7}{10}

3 0
3 years ago
Me Green's sunflower grew 29 centimeters in one week. The next week it grew 5 centimeters more than the previous week. What is t
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The sunflowers grew 5 more centimeters than last week. Last week they grew 29 centimeters. 29+5=34. THe first week the flowers grew 29 centimeters. In the second week they grew 34 centimeters. in those two weeks they grew 63 centimeters.

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Step-by-step explanation:

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To find the future value of this investment the formula is
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R interest rate 0.07
K compounded monthly 12
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An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" () and "tails" () which we write , , etc. For ea
boyakko [2]

Answer:

Some details are missing

Step-by-step explanation:

An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails) (t) which we write hth, ttt, etc. For each outcome, let R be the random variable counting the number of heads in each outcome. For example, if the outcome is hht, then R(hht) = 2. Suppose that the random variable X is defined in terms of R as follows: X = 2R² - 6R - 1. The values of X are thus:

Outcome: || Value of X

tht || -5

thh || -5

hth || -5

htt || -5

hhh || -1

tth || -5

hht || -5

ttt || -1

Calculate the probability distribution function of X, i.e. the function Px (x). First, fill in the first row with the values of X. Then fill in the appropriate probabilities in the second row.

Solution

To calculate the probability distribution function of X.

We have to observe the total outcomes to check the number of "Heads (h) " in each outcome.

The first, fourth and, sixth outcome has 1 head (h)

The second, third and seventh outcome has 2 head (hh)

The fifth outcome has 3 head (hhh)

The eight outcome has 0 appearance of h

We then solve the probability of each occurrence

i.e. The probability of having h, hh, hhh and no occurrence of h

This will be represented as follows

P(h=0)

P(h=1)

P(h=2)

P(h=3)

In a coin, the probability of getting a head = ½ and the probability of getting a tail = ½ in 1 toss

Using the following formula

P(X=x) = nCr a^r * b ^ (n-r)

Where n represents total number of toss = 3

r represents number of occurrence

a represents getting a head = ½

b represents probability of getting a tail = ½

1. For h = 0

P(h=0) = 3C0 * ½^0 * ½³

P(h=0) = 1 * 1 * ⅛

P(h=0) = ⅛

2. For h = 1

P(h=1) = 3C1 * ½^1 * ½²

P(h=1) = 3 * ½ * ¼

P(h=1) = ⅜

3. P(h=2) = 3C2 * ½² * ½^1

P(h=2) = 3 * ¼ * ½

P(h=2) = ⅜

4.P(h=3) = 3C3 * ½³ * ½^0

P(h=0) = 1 * ⅛ * 1

P(h=0) = ⅛

It should be noted that when X is -5, h is either 1 or 2 and P(X) = ⅜

When X is -1, h is either 0 or 3 and P(X) = ⅛

The probability distribution function of X is as follows

Values of X || P(x)

-5 || ⅜

1 || ⅛

6 0
3 years ago
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