Tess has 42 words of an essay typed and is typing about 1.3 words per second. Margo 122 words of an essay typed and is erasing a
bout 1.2 words per second. In how many seconds will the number of words in Tess’s essay exceed the number of words in Margos essay?
1 answer:
Answer:
32 seconds
Step-by-step explanation:
For some number of seconds (s), Tess's essay length (t) will be ...
t = 42 +1.3s
and Margo's essay length (m) will be ...
m = 122 -1.2s
We will have t > m when ...
t > m
42 +1.3s > 122 -1.2s
2.5s > 80 . . . . . . . . add 1.2s-42
s > 32 . . . . . . . . . . . divide by 2.5
After 32 seconds, Tess's essay will exceed Margo's in length.
You might be interested in
Answer:
-6
Step-by-step explanation:
→ Remove the brackets
-1 - 5
→ Simplify
-6
Answer:
True
Step-by-step explanation:
because is it asking that the hight (y) is in what place in a more spicific wording
Answer:
B: $2.50
Step-by-step explanation:
Step 1: form an equation
126 = 12(8 + x)
Step 2: isolate the x
126/12 = 8 + x
126/12 - 8 = x
Step 3: solve
10.5 - 8 = x
2.5 = x = raise per hour
Answer:
4x^2+11x+23 r53
Step-by-step explanation:
4x^3-3x^2+x+7 / x-2
2 | 4 -3 1 7
8 22 46
___________
4 11 23 53
This means 4x^2+11x+23 with a remainder of 53