Answer:
The ship is located at (3,5)
Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III
Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II
To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.
Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9
We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3
Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5
Based on the above, the position of the ship is (3,5).
Hope this helps :)
Answer:
406
Step-by-step explanation:
6+(4x100)
Answer:
19 ft.
Step-by-step explanation:
Pytahgorean theorm. A^2 + B ^2 = C^2
49 + 100 = 149
Square root the 149, which is ~12
That means the hypotenuse is twelve feet, and with the base of the pole being seven, the pole was originally 19 feet tall.
Given:
In triangle 
.
To find:
The 
.
Solution:
According to the law of sines:
Taking 
, we get
Taking sin inverse on both sides, we get
Therefore, the correct option is b.
Well, number 1 is A, or p = 6t. This is because the number of points is equal to the number of touchdowns times six. *6 = (6)(1) *12 = (6)(2) *18 = (6)(3), etc
