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zubka84 [21]
3 years ago
5

3x-2y=10 3x-2y=14 solve using substitution or elimination. What's the answer?

Mathematics
2 answers:
CaHeK987 [17]3 years ago
8 0
I hope this helps you



-3x+2y= -10


3x-2y=14



-3x+2y+3x-2y= -10+14


0+0= 6


0=6 false it's not inconsistent




sammy [17]3 years ago
6 0
Let's do elimination since the left sides have the same coefficients.

3x - 2y = 10
3x - 2y = 14

To eliminate, subtract the second equation from the first by multiplying the equation by -1. 

3x - 2y = 10
-3x +2y = -14
------------------
0 + 0 = 10 - 14
0 = -4

Hey that's not true! 0 does not equal -4, which means there is no solution to the two equations.
You can confirm this by graphing. The equations do not intersect and therefore there will be no solution.
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4 years ago
Y is inversely proportional to x.<br> When =9, y = 8.<br> Find y when x= 6.
Furkat [3]

Answer:

y=12

Step-by-step explanation:

y is inversely proportional to x

y=k/x

k is a constant of proportionality

k=yx

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6 0
3 years ago
The measure of three angles of a triangle are (2×), (3×) and (×+60) what is the value of x ?
Gelneren [198K]
Since the sum of the angles of a triangle = 180°

Then  (2x)º + (x + 60)º + (3x)º  = 180°
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4 0
3 years ago
What is (m - 5) divided by 4 where m = 17
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2 years ago
In a sample of 230 teenagers, 202 would like to have smaller class sizes at their school. Find the sample
marishachu [46]

Answer:

The sample proportion is 0.88.

The margin of error is of 0.04.

The interval likely to contain the true population proportion is (0.84,0.92).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

Margin of error:

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

Sample of 230 teenagers, 202 would like to have smaller class sizes at their school.

This means that n = 230, and that the sample proportion is:

\pi = \frac{202}{230} = 0.88

The sample proportion is 0.88.

Standard 95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Margin of error:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

M = 1.96\sqrt{\frac{0.88*0.12}{230}}

M = 0.04

The margin of error is of 0.04.

Confidence interval:

Sample proportion plus/minus margin of error. So

0.88 - 0.04 = 0.84

0.88 + 0.04 = 0.92

The interval likely to contain the true population proportion is (0.84,0.92).

5 0
3 years ago
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