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Ksju [112]
3 years ago
6

What identity can be used to rewrite the expression 27x^3-64?

Mathematics
1 answer:
nikdorinn [45]3 years ago
8 0

Option A:

Difference of cubes

Solution:

Given expression is 27 x^{3}-64.

27 can be written as 3^3.

64 can be written as 4^3.

27 x^{3}-64=3^3x^3-4^3

27 x^{3}-64=(3x)^3-4^3

To find the identity to rewrite the given expression:

Option A: Difference of cubes

27 x^{3}-64 can be rewritten as (3x)^3-4^3.

That means the difference of two cubes.

So, it is true.

Option B: Difference of squares

27 x^{3}-64 cannot be written as square terms.

So, it is false.

Option C: Sum of cubes

27 x^{3}-64 cannot be written as sum of cubes.

So, it is false.

Option D: Pythagorean Triples

27 x^{3}-64 cannot be written as Pythagorean Triples.

So, it is false.

Hence difference of cubes if the correct answer.

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Andrei [34K]

Answer:

x=-2

Step-by-step explanation:

2(3x – 1) = 4x - 6

Distribute

6x-2=4x-6

Moving like terms (4x)

2x-2=-6

Moving like terms (-2)

2x=-4

Divide both sides by 2 to isolate x

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KatRina [158]

Answer:

15

Step-by-step explanation:

2(2) - 18 = -14 |-14| = 14

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3 years ago
11r+7s help me please
Maru [420]

Answer: First term = 11r and  second term= 7s

The coefficient in first term = 11

The coefficient in second term =7

Step-by-step explanation:

The given expression 11r + 7s is with two terms i.e. a binomial expression with variables r and s

Here the first term = 11r

And the coefficient of r in term =11

The second term= 7s

The coefficient of s in second term=7

The coefficients are the numbers that multiply the variables .

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The masses of the oranges on sale at a farm stand are normally distributed with a mean of 239 grams and a standard deviation of
AleksAgata [21]
In order to calculate the z-score of a normal distribution, you need to apply the formula:

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where:
o = observed value
m = mean
s = standard deviation

In your case:

z = (259 - 239) / 25 = 0.8

The answer is, indeed, z = 0.8
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Sorry if the image is blurry
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Answer:

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