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Ksju [112]
3 years ago
6

What identity can be used to rewrite the expression 27x^3-64?

Mathematics
1 answer:
nikdorinn [45]3 years ago
8 0

Option A:

Difference of cubes

Solution:

Given expression is 27 x^{3}-64.

27 can be written as 3^3.

64 can be written as 4^3.

27 x^{3}-64=3^3x^3-4^3

27 x^{3}-64=(3x)^3-4^3

To find the identity to rewrite the given expression:

Option A: Difference of cubes

27 x^{3}-64 can be rewritten as (3x)^3-4^3.

That means the difference of two cubes.

So, it is true.

Option B: Difference of squares

27 x^{3}-64 cannot be written as square terms.

So, it is false.

Option C: Sum of cubes

27 x^{3}-64 cannot be written as sum of cubes.

So, it is false.

Option D: Pythagorean Triples

27 x^{3}-64 cannot be written as Pythagorean Triples.

So, it is false.

Hence difference of cubes if the correct answer.

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I do not know how to do this! Please help me!
Andrew [12]

\qquad\qquad\huge\underline{\boxed{\sf Answer}}

Perimeter of given figure is equal to :

Perimeter of square - side length + quarter Circumference of the circle

that is :

\qquad \sf  \dashrightarrow \:(10 \times 4) - (5 + 5) +  \dfrac{2 \pi r}{4}

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So, the required perimeter is 37.85 units

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Alice separated her pictures into 3 piles. Each pile contained 9 pictures. How many pictures did she have in all? Write and solv
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Projectile Is shot upward from the surface of Earth with an initial velocity of 136 meters per second. Use the position
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Answer:

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Step-by-step explanation:

The velocity function of the projectile is obtained by deriving the position function:

v(t) = -9.8\cdot t + 136

Now, the velocities after 3 and 15 seconds are, respectively:

v(3\,s) = -9.8\cdot (3) + 136

v(3\,s) = 106.6\,\frac{ft}{s}

v(15\,s) = -9.8\cdot (15) + 136

v(15\,s) = -11\,\frac{ft}{s}

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