The Factorization of 121b⁴ − 49 is (11b^2 + 7)(11b^2 - 7).
The equation 121b⁴ − 49
To find the Factorization of 121b⁴ − 49.
<h3>
What is the factor of a^2-b^2?</h3>
The factor of a^2-b^2 is (a+b)(a-b)
We have write the given equation in the form of a^2-b^2
![= 121b^4 - 49\\= (11b^2)^2 - 7^2\\= (11b^2 + 7)(11b^2 - 7)](https://tex.z-dn.net/?f=%3D%20121b%5E4%20-%2049%5C%5C%3D%20%2811b%5E2%29%5E2%20-%207%5E2%5C%5C%3D%20%2811b%5E2%20%2B%207%29%2811b%5E2%20-%207%29)
Therefore the factor of the 121b^4 − 49 is (11b^2 + 7)(11b^2 - 7).
To learn more about the factor visit:
brainly.com/question/25829061
Answer:
14/24 And 21/36
Step-by-step explanation:
Just multiply the fractions by any number. In this case 2 and 3.
Your answer is 32! 4 divided by 1/8 is 32.
Answer:
A
Step-by-step explanation:
35 + 40 + 50 = 125
35/125 = 0.28