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Svet_ta [14]
3 years ago
12

Help on this question

Mathematics
1 answer:
Dimas [21]3 years ago
6 0
The answer is d. DFG
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Omg I need an answer ASAP for number 17 parts a and b
Aleksandr [31]

a) 6(2)+6^2+24

   =12+36+24

   =72 square inches

b) 8 inches by 9 inches

8 0
3 years ago
The revenue, in dollars, of a company that manufactures televisions can be modeled by the polynomial 3x²+180x . The cost, in dol
tresset_1 [31]

We use the profit concept, and doing this, it is found that if 150 televisions are sold, the profit is $50,700.

-------------------------------------------

Profit is given by revenue subtracted by cost.

In this question:

  • Revenue: R(x) = 3x^2 + 180x
  • Cost: C(x) = 3x^2 - 160x + 300

Thus, the profit of selling x televisions is:

P(x) = R(x) - C(x)

P(x) = 3x^2 + 180x - (3x^2 - 160x + 300)

P(x) = 3x^2 + 180x - 3x^2 + 160x - 300

P(x) = 340x - 300

-------------------------------------------

For 150 televisions, we have P(150), so:

P(150) = 340(150) - 300 = 50700

If 150 televisions are sold, the profit is $50,700.

A similar question is given at brainly.com/question/14469903

8 0
3 years ago
One of the legs of a right triangle measures 14 cm and the other leg measures 5 cm.
Gre4nikov [31]

Answer:

14.9cm

Step-by-step explanation:

hope it helps you good day.

8 0
2 years ago
A phycologist is interested in determining the proportion of algae samples from a local rivulet that belong to a particular phyl
LuckyWell [14K]

Answer:

A sample of 16577 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

99% confidence level

So \alpha = 0.01, z is the value of Z that has a p-value of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

She wants to estimate the proportion using a 99% confidence interval with a margin of error of at most 0.01. How large a sample size would be required?

We have no estimation for the proportion, and thus we use \pi = 0.5, which is when the largest sample size will be needed.

The sample size is n for which M = 0.01. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.01 = 2.575\sqrt{\frac{0.5*0.5}{n}}

0.01\sqrt{n} = 2.575*0.5

\sqrt{n} = \frac{2.575*0.5}{0.01}

(\sqrt{n})^2 = (\frac{2.575*0.5}{0.01})^2

n = 16576.6

Rounding up:

A sample of 16577 is required.

8 0
2 years ago
Can help me understand this?
Tanzania [10]

Answer:

Its easy just fill in the blacks

Step-by-step explanation:

P1 is 5 P2 is 2 P3 is 4 and so on now the odd and even u add the odd number together and the even together like 2+2+1 (the even side) =5 so put 5 in the even and do the same thing to odd 5+4+6 = 15 and put 15 on odd #

Hope this helps!

4 0
3 years ago
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