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3 years ago

How do I solve the quadratic equation by factoring? 2x^2+x=6

Mathematics

1 answer:

aliina [53]3 years ago

5 0

Move the 6 to the other side:
2x^2 +x+6,
(x-3) (x+4)
x=3 and x=-4

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Given ΔABC with A(–4, –2), B(4, 4), and C(18, –8), write the equation for the line containing median segment The term is line se

Monica [59]

Here we want to find the equation of the line containing the median CP.

P, being the midpoint of AB can be found using the midpoint formula as:

$\displaystyle{ P=( \frac{-4+4}{2} , \frac{-2+4}{2} )=(0, 1)$ .

The slope m of the line through CP can be found by the slope formula using points C(18, -8) and P(0, 1):

$\displaystyle{ m= \frac{y_2-y_1}{x_2-x_1}= \frac{-8-1}{18-0}= \frac{-9}{18}= \frac{-1}{2}$ .

Now, we can write the equation of the line with slope -1/2, passing through
P(0, 1):

$y-1= \frac{-1}{2}(x-0)\\\\y= -\frac{1}{2}x+1$ .

Answer: $y=-\frac{1}{2}x+1$

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3 years ago

Perimeter 254 meters and dimension measures 6 meters

Mamont248 [21]

Answer:

didn't even ask a question

Step-by-step explanation:

impossible to answer without a question

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2 years ago

A sledgehammer weighs 18 pounds on Earth and 4 pounds on the planet Namar.

Advocard [28]

It would weight 18lbs i believe

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2 years ago

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Find the exact values of sin2 θ for cos θ = 3/18 on the interval 0° ≤ θ ≤ 90°

mote1985 [20]

Answer:

$sin(2\theta)=\frac{\sqrt{35} }{18}$

Step-by-step explanation:

Recall the formula for the sine of the double angle:

$sin(2\theta)=2*sin(\theta)*cos(\theta)$

we know that $cos(\theta)=\frac{3}{18}$ , and that $\theta$ is in the interval between 0 and 90 degrees, where both the functions sine and cosine are non-negative numbers. Based on such, we can find using the Pythagorean trigonometric property that relates sine and cosine of the same angle, what $sin(\theta)$ is:

$cos^2(\theta)+sin^2(\theta)=1\\sin^2(\theta)=1-cos^2(\theta)\\sin(\theta)=\sqrt{1-cos^2(\theta)} \\sin(\theta)=\sqrt{1-(\frac{3}{18} )^2}\\sin(\theta)=\sqrt{1-\frac{9}{324} }\\sin(\theta)=\sqrt{\frac{324-9}{324} }\\sin(\theta)=\sqrt{\frac{315}{324} }\\\\sin(\theta)=\frac{3}{18}\sqrt{35 }$

With this information, we can now complete the value of the sine of the double angle requested:

$sin(2\theta)=2*sin(\theta)*cos(\theta)\\sin(2\theta)=2*\frac{3}{18} \,\sqrt{35} \,\frac{3}{18}\\sin(2\theta)=\frac{2*3*3}{18*18}\,\sqrt{35} \\sin(2\theta)=\frac{\sqrt{35} }{18}$

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2 years ago

Given that x and y are positive. If the value of x is increased, what happens to the value of the expression?

Licemer1 [7]

"It would increase."

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3 years ago