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irinina [24]
3 years ago
13

Change control in application development is a formal process for changing written documentation into online documentation, and

frequently uses specialized cyber documentation agents to create menus, screens and online user documentation.
A) True
B) False
Computers and Technology
1 answer:
Furkat [3]3 years ago
4 0

Answer:

B) False

Explanation:

The term Change control is a systematic way employed to keep track of all changes made to a product or system. It is aimed at ensuring that no unnexpected changes takes place and that changes made during application development are properly recorded.

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1. How many bits would you need to address a 2M × 32 memory if:
Dominik [7]

Answer:

  1. a) 23       b) 21
  2. a) 43        b) 42
  3. a) 0          b) 0

Explanation:

<u>1) How many bits is needed to address a 2M * 32 memory </u>

2M = 2^1*2^20, while item =32 bit long word

hence ; L = 2^21 ; w = 32

a) when the memory is byte addressable

w = 8;  L = ( 2M * 32 ) / 8 =  2M * 4

hence number of bits =  log2(2M * 4)= log2 ( 2 * 2^20 * 2^2 ) = 23 bits

b) when the memory is word addressable

W = 32 ; L = ( 2M * 32 )/ 32 = 2M

hence the number of bits = log2 ( 2M ) = Log2 (2 * 2^20 ) = 21 bits

<u>2) How many bits are required to address a 4M × 16 main memory</u>

4M = 4^1*4^20 while item = 16 bit long word

hence L ( length ) = 4^21 ; w = 16

a) when the memory is byte addressable

w = 8 ; L = ( 4M * 16 ) / 8 = 4M * 2

hence number of bits = log 2 ( 4M * 2 ) = log 2 ( 4^1*4^20*2^1 ) ≈ 43 bits

b) when the memory is word addressable

w = 16 ; L = ( 4M * 16 ) / 16 = 4M

hence number of bits = log 2 ( 4M ) = log2 ( 4^1*4^20 ) ≈ 42 bits

<u>3) How many bits are required to address a 1M * 8 main memory </u>

1M = 1^1 * 1^20 ,  item = 8

L = 1^21 ; w = 8

a) when the memory is byte addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

hence number of bits = log 2 ( 1M ) = log2 ( 1^1 * 1^20 ) = 0 bit

b) when memory is word addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

number of bits = 0

5 0
2 years ago
A _____ miniature battery operated transmitter that can be propelled through a non-metallic pipe or purpose of locating
Anna11 [10]
I think it is the model ET-2. Not quite sure.
7 0
2 years ago
Using a text editor, create a file that contains a list of at least 15 six-digit account numbers. Read in each account number an
Zanzabum

Answer:

See explaination

Explanation:

/File: ValidateCheckDigits.java

import java.io.BufferedWriter;

import java.io.File;

import java.io.FileWriter;

import java.io.IOException;

import java.util.Scanner;

public class ValidateCheckDigits {

public static void main(String[] args) {

String fileName = "numbers.txt"; //input file name

String validFileName = "valid_numbers.txt"; // file name of the output file

//Open the input file for reading and output file for writing

try(Scanner fileScanner = new Scanner( new File(fileName));

BufferedWriter fileWriter = new BufferedWriter( new FileWriter(validFileName))) {

//Until we have lines to be read in the input file

while(fileScanner.hasNextLine()) {

//Read each line

String line = fileScanner.nextLine().trim();

//calculate the sum of first 5 digits

int sum = 0;

for(int i = 0; i < 5; i++) {

sum += Integer.parseInt( line.charAt(i) + "");

}

//Get the last digit

int lastDigit = Integer.parseInt(line.charAt(5)+"");

//Check if the remainder of the sum when divided by 10 is equal to last digit

if(sum%10 == lastDigit) {

//write the number in each line

fileWriter.write(line);

fileWriter.newLine();

System.out.println("Writing valid number to file: " + line);

}

}

System.out.println("Verifying valid numbers completed.");

} catch(IOException ex ) {

System.err.println("Error: Unable to read or write to the file. Check if the input file exists in the same directory.");

}

}

}

Check attachment for output and screenshot

4 0
3 years ago
Describe how serial data access finds data
jeyben [28]

Answer:

Serial data access will go through all the data by order until the target data is reached

Explanation:

This is opposite of direct data access which immediately finds the desired

data

4 0
3 years ago
Read 2 more answers
In this assignment we are going to practice reading from a file and writing the results of your program into a file. We are goin
zhenek [66]

Answer:

In Python:

import os.path

from os import path

fname = input("Filename: ")

if path.exists(fname):

with open(fname) as file_in:

 lines = []

 for line in file_in:

  lines.append(line.rstrip('\n'))

f = open("stat.txt","r+")

f.truncate(0)

f = open("stat.txt", "a")

f.write("Names\tTotal\tSubjects\tAverage\n")

for i in range(len(lines)):

 rowsum = 0; count = 0

 nm = lines[i].split()

 for j in nm:

  if (j.isdecimal()):

   count+=1

   rowsum+=int(j)

 average = rowsum/count

 f.write(nm[0]+"\t %3d\t %2d\t\t %.2f\n" % (rowsum, count, average))

f.close()

else:

print("File does not exist")

Explanation:

See attachment for explanation where comments were used to explain each line

Download txt
6 0
3 years ago
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