Please help me!! If you need a close up please don’t hesitate to ask!

F(x)=[[2x]] picewise functions

Lena [83]

Answer:

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Step-by-step explanation:

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6 0

3 years ago

A silo is a composite of a cylindrical tower with a cone for a roof. Find the volume of the silo if the

xxMikexx [17]

Answer:

5127079.21 cubic feet

Step-by-step explanation:

The silo is in the shape of a cylinder and a cone.

The volume of the silo will be the sum of the volumes of the cylinder and the cone.

Therefore, its volume is:

$V = \pi r^2h + \frac{1}{3} \pi rH$

where r = radius of cylinder and cone

h = height of cylinder

H = height of cone

The radius of the base is 120 feet, the height of the roof (cone) is 25 feet. The height of the entire silo is 130 feet. This means that the height of the cylinder is:

130 - 25 = 105 feet

Therefore, the volume of the silo is:

$V = (\pi * 120^2 * 105) + (\frac{1}{3} * 120^2 * 25)\\\\V = 4750088.09 + 376991.12\\\\V = 5127079.21 ft^3$

The volume of the silo is 5127079.21 cubic feet.

3 0

3 years ago

HELP QUICK AND FAST WHAT THE ANSWER

Semmy [17]

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7 0

3 years ago

What is the greatest common factor of 32,24,40

Mandarinka [93]

The GCF of 24, 32, and 80 must be 8, since it is the largest number common to both lists. Example 1 Find the greatest common factor of each set of numbers by listing factors.

8 0

3 years ago

Please help me with both questions!!!!

Naya [18.7K]

Answer:

Step-by-step explanation:

16.

points are (0,-3),(2,1),(4,-3)

eq. of line through (0,-3) and (2,1) is

y+3=\frac{1+3}{2-0}(x-0)

or y+3=2x

2x-y=3

as the line is dotted so either < or >.

consider 2x-y>3

put x=0,y=0

0>3

which is not possible .

(0,0) does not satisfy the inequality

Hence shaded region is the required region.

now eq of line through (2,1)and (4,-3) is

y-1=\frac{-3-1}{4-2}(x-2)

y-1=-2(x-2)

y-1=-2x+4

2x+y=5

it is also a dotted line so either < or >

consider 2x+y<5

put x=0,y=0

0<5

which is true.

so (0,0) satisfy this inequality.

so the two inequalities are

2x-y>3

and 2x+y<5

17.

consider the points (0,4),(2,3),(4,4)

eq. of line through (0,4) and (2,3) is

y-4=\frac{3-4}{2-0}(x-0)

y-4=-1/2(x)

2y-8=-x

or x+2y=8

as the line is solid

so either≤ or ≥

consider x+2y≥8

put x=0,y=0

0≥8

which is impossible.

(0,0) does not satisfy the graph.

which is true as graph lies above the line.

again eq. of line through (2,3) and (4,4) is

y-3=\frac{4-3}{4-2}(x-2)

y-3=1/2(x-2)

2y-6=x-2

x-2y=-4

consider x-2y≤-4

put x=0, y=0

0≤-4

which is impossible.

so (0,0) does not satisfy the graph.

so inequality is true as shaded portion is above and left of the line.

so two inequalities are

x+2y≥ 8

and x-2y≤-4

5 0

3 years ago