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zaharov [31]
2 years ago
15

Please help I’ll give brailiest

Mathematics
2 answers:
Scrat [10]2 years ago
3 0
The total angle sum of a triangle is 180°
As such, 180= 78 + 2s +4s
102= 6s
s=17
vitfil [10]2 years ago
3 0

Step-by-step explanation:

2s+4s+78=180

6s=180-78

s=102/6

s=39.54

hope this helps you

have a nice day

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Solving systems by elimination <br> 9x+3y=-3 <br> 2x-3y=-8
Alona [7]

Answer:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

x

=

−

1

Step-by-step explanation:

5 0
3 years ago
7x-5y=-15 and -14x+7y=0 Solve by elimination
geniusboy [140]

Answer: (5,10)

Step-by-step explanation:

multiply first equation with 2 and add it to second to eliminate X

7x-5y=-15  //*2

14x-10y=-30

-14x+7y=0

----------------

-3y=-30

y=-30/-3

y=10

7x=50-15

7x=35

x=35/7

x=5

4 0
3 years ago
Can someone tell me what 2/3 divided by 5 is it’s for a quiz.
docker41 [41]

Answer:2/15 hope this helps

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Consider the equation and the relation “(x, y) R (0, 2)”, where R is read as “has distance 1 of”. For example, “(0, 3) R (0, 2)”
Leviafan [203]

Answer:

The equation determine a relation between x and y

x = ± \sqrt{1-(y-2)^{2}}

y = ± \sqrt{1-x^{2}}+2

The domain is 1 ≤ y ≤ 3

The domain is -1 ≤ x ≤ 1

The graphs of these two function are half circle with center (0 , 2)

All of the points on the circle that have distance 1 from point (0 , 2)

Step-by-step explanation:

* Lets explain how to solve the problem

- The equation x² + (y - 2)² and the relation "(x , y) R (0, 2)", where

 R is read as "has distance 1 of"

- This relation can also be read as “the point (x, y) is on the circle

 of radius 1 with center (0, 2)”

- “(x, y) satisfies this equation , if and only if, (x, y) R (0, 2)”

* <em>Lets solve the problem</em>

- The equation of a circle of center (h , k) and radius r is

  (x - h)² + (y - k)² = r²

∵ The center of the circle is (0 , 2)

∴ h = 0 and k = 2

∵ The radius is 1

∴ r = 1

∴ The equation is ⇒  (x - 0)² + (y - 2)² = 1²

∴ The equation is ⇒ x² + (y - 2)² = 1

∵ A circle represents the graph of a relation

∴ The equation determine a relation between x and y

* Lets prove that x=g(y)

- To do that find x in terms of y by separate x in side and all other

  in the other side

∵ x² + (y - 2)² = 1

- Subtract (y - 2)² from both sides

∴ x² = 1 - (y - 2)²

- Take square root for both sides

∴ x = ± \sqrt{1-(y-2)^{2}}

∴ x = g(y)

* Lets prove that y=h(x)

- To do that find y in terms of x by separate y in side and all other

  in the other side

∵ x² + (y - 2)² = 1

- Subtract x² from both sides

∴ (y - 2)² = 1 - x²

- Take square root for both sides

∴ y - 2 = ± \sqrt{1-x^{2}}

- Add 2 for both sides

∴ y = ± \sqrt{1-x^{2}}+2

∴ y = h(x)

- In the function x = ± \sqrt{1-(y-2)^{2}}

∵ \sqrt{1-(y-2)^{2}} ≥ 0

∴ 1 - (y - 2)² ≥ 0

- Add (y - 2)² to both sides

∴ 1 ≥ (y - 2)²

- Take √ for both sides

∴ 1 ≥ y - 2 ≥ -1

- Add 2 for both sides

∴ 3 ≥ y ≥ 1

∴ The domain is 1 ≤ y ≤ 3

- In the function y = ± \sqrt{1-x^{2}}+2

∵ \sqrt{1-x^{2}} ≥ 0

∴ 1 - x² ≥ 0

- Add x² for both sides

∴ 1 ≥ x²

- Take √ for both sides

∴ 1 ≥ x ≥ -1

∴ The domain is -1 ≤ x ≤ 1

* The graphs of these two function are half circle with center (0 , 2)

* All of the points on the circle that have distance 1 from point (0 , 2)

8 0
3 years ago
If 150 is divided by x, then the remainder is 3. What is the remainder when 296 is divided by x?
aliina [53]
The answer I think is 2. 150/7 is 21 R 3. 296/7 is 42 R 2.
8 0
3 years ago
Read 2 more answers
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