1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Reika [66]
4 years ago
6

WHAT IS AN ALKANE WHAT IS AN ALKENE

Chemistry
1 answer:
xenn [34]4 years ago
3 0

❤️Hello!❤️ Alkane  

In organic chemistry, an alkane, or paraffin, is an acyclic saturated hydrocarbon. Hope this helps! ↪️ Autumn ↩️

You might be interested in
What may explode in a combustible atmosphere?
shusha [124]

Explanation:

<h2><em><u>Dust explosions can occur where any dispersed powdered combustible material is present in high-enough concentrations in the atmosphere or other oxidizing gaseous medium, such as pure oxygen</u></em></h2>
7 0
3 years ago
What is a maze passsage way that Carrys ribosomes and proteins
erastovalidia [21]
Endoplasmic reticulum.

I have biology this semester too :)
5 0
4 years ago
Choose the correct words. Please help and you will be rewarded
il63 [147K]
1 = Salt
2 = Lead
3 = Magnesium 
4 = Silver
4 0
3 years ago
MgCl2 + NaOH → Mg(OH)2 +Naci<br> Balance
Oksana_A [137]
MgCl2+2NaOH=Mg(OH)2+2NaCl
3 0
3 years ago
For the reaction C2H4(g) + H2O(g) --&gt; CH3CH2OH(g)
Dominik [7]

Answer : The value of equilibrium constant for this reaction at 262.0 K is 3.35\times 10^{2}

Explanation :

As we know that,

\Delta G^o=\Delta H^o-T\Delta S^o

where,

\Delta G^o = standard Gibbs free energy  = ?

\Delta H^o = standard enthalpy = -45.6 kJ = -45600 J

\Delta S^o = standard entropy = -125.7 J/K

T = temperature of reaction = 262.0 K

Now put all the given values in the above formula, we get:

\Delta G^o=(-45600J)-(262.0K\times -125.7J/K)

\Delta G^o=-12666.6J=-12.7kJ

The relation between the equilibrium constant and standard Gibbs free energy is:

\Delta G^o=-RT\times \ln k

where,

\Delta G^o = standard Gibbs free energy  = -12666.6 J

R = gas constant  = 8.314 J/K.mol

T = temperature  = 262.0 K

K = equilibrium constant = ?

Now put all the given values in the above formula, we get:

-12666.6J=-(8.314J/K.mol)\times (262.0K)\times \ln k

k=3.35\times 10^{2}

Therefore, the value of equilibrium constant for this reaction at 262.0 K is 3.35\times 10^{2}

3 0
4 years ago
Other questions:
  • HELP ASAP PLEASE!!!!
    15·1 answer
  • A substance is highly malleable and has a shiny luster. Which of the following best explains the probable position of the substa
    5·2 answers
  • Consider the following reaction:
    12·1 answer
  • Magnesium fluoride is used in the ceramics and glass industry. What is the mass of 1.72 mol of magnesium fluoride?
    15·1 answer
  • Here’s the balanced equation for the reaction between nitrogen and hydrogen that produces ammonia (NH3):
    6·1 answer
  • helppppp. which of the following statements regarding physical and chemical changes is true? a. both physical and chemical chang
    7·2 answers
  • 3. How many moles of H20 are in 15.2 grams of pure ice?
    12·1 answer
  • If you add more molecules but do not change the temperature or the pressure, what will happen to the system?
    15·1 answer
  • Please help me asap thank you
    9·1 answer
  • Calculate the volume of 22.36 g of titanium (density = 4.540 g/cm^3).
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!