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murzikaleks [220]
3 years ago
14

What volume will 2 moles of nitrogen occupy at 780 torr and 10C.

Chemistry
1 answer:
galina1969 [7]3 years ago
5 0

The volume : V = 45.22 L

<h3>Further explanation</h3>

Given

Moles = n = 2

Pressure = P = 780 torr = 1,02632 atm

Temperature = T = 10 + 273 = 283 K

Required

Volume

Solution

Ideal gas law : PV = nRT

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

Input the value :

V = (nRT)/P

V = (2 x 0.082 x 283)/1,02632

V = 45.22 L

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Use collision theory to describe the relationship between temperature and volume of a gas.
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Answer:

Charles's law states that the volume of a given amount of gas is directly proportional to its temperature on the kelvin scale when the pressure is held constant.

8 0
3 years ago
How many elements are found in 2CuSO4?<br> A.5<br> B.4<br> C.2<br> D.3
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d

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4 0
3 years ago
Please answer this question
lukranit [14]
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6 0
3 years ago
2.50 L of gas originally at 50 K is warmed to 80 K. If the pressure remains constant, which gas law needs to be used to find the
Brilliant_brown [7]

Answer:

A

Explanation:

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B: The Combined Gas Law is p₁V₁/T₂ = p₂V₂/T₂ will work, but it's overkill for the situation. You can assume any constant value for the pressure, and it will cancel from each side of the equation,

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7 0
3 years ago
Helppppppppppppppppp
igor_vitrenko [27]

Answer:

0.028578 km

Explanation:

The following data were obtained from the question:

Length of whale (in mm) = 28578 mm

Length of whale (in km) =?

We can convert 28578 mm to km by doing the following:

Recall:

1 mm = 1×10¯⁶ Km

Therefore,

28578 mm = 28578 mm × 1×10¯⁶ Km / 1 mm

28578 mm = 0.028578 km

Thus, 28578 mm is equivalent to 0.028578 km

The length of whale (in km) = 0.028578 km

3 0
3 years ago
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