Proton is a positively charged particle
Explanation:
Since this is an equilibrium problem, we apply le chatelier principle. This principle states that whenever a system at equilibrium is disturbed due to change in several factors, it would move in a way to annul such change.
C2H4(g) + Cl2 ⇔ 2C2H4Cl2(g)
When the concentration of C2H4 is increased, there is more reactant sin the system. In order to annul this change, the equilibrium position will shift to the right favoring product formation.
When the concentration of C2H4Cl2 is increased, there is more product in the system. To annul this change, the equilibrium position will shift to the left, favoring reactant formation.
If it is just a simple double-replacement reaction, then the balanced equation is simply:
Pb(ClO3)2(aq) + 2 NaI(aq) = PbI2 + 2 Na(ClO3)
However, if this is a precipitation reaction, we must identify which compound will precipitate (is insoluble), either NaClO3 or PbI2
NaClO3 is soluble, PbI2 is not. Only the lead cations and iodine anions will participate in the reaction.
thus, the balanced equation is: Pb^(2+) + 2I^(-) ==> PbI2
Answer:
alkali metal
Explanation:
The alkali metals in period 4 will have the lowest ionization energy of the elements in the period.
Across a period ionization energy increases progressively from left to right due to decreasing atomic radii caused by the increasing nuclear charge which is not compensated for by successive electronic shells.
- Ionization energy is the energy needed to remove the most loosely bound electrons of an atom in the gas phase in the ground state.
- The measure of the readiness of an atom to lose an electron is the ionization energy.
Down a group, it decreases.
