Answer:
58.92 g EDTA
Explanation:
315.1 mL = .3151 L
M = Moles / Liter
.3151 L x <u>0.5 mol EDTA</u> x <u>374 g EDTA</u> = 58.92 g EDTA
1 L EDTA 1 mol EDTA
Answer:
me please I need to level up
Explanation:
Answer:
using the formula of numbers of molecules
Explanation:
mass /Mr 44/44=1 molecules of carbon dioxide present
(Mr of carbon dioxide is ( 2*16)+12=44
Now time by Abogadros constant 1*6.002*10^23
molecules of CO2 are present = 6.002*10^23
Answer:
B
Look up cumulonimbus clouds it looks like b
The mole fraction of urea in a solution that contain 2.1 mol Urea and 4.4 mole of water is 0.32
calculation
mole fraction = moles of urea/ total mole
moles of urea = 2.1 mole
calculate the total mole
= 2.1 mole + 4.4 mole = 6.5
Mole fraction is therefore = 2.1/.6.5 = 0.32