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NARA [144]
3 years ago
11

8 - 3x = 14 what is the value of x

Mathematics
2 answers:
wel3 years ago
3 0

Answer: it is 2

Step-by-step explanation: because 7 x 2 is 14

Karo-lina-s [1.5K]3 years ago
3 0

Answer:

x= -2

Step-by-step explanation:

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Use a graphing calculator to solve the equation -3 cost= 1 in the interval from . Round to the nearest hundredth.
RSB [31]
In place of t, or theta, I'm going to utilize x instead. So the equation is -3*cos(x) = 1. Get everything to one side and we have -3*cos(x)-1 = 0

Let f(x) = -3*cos(x)-1. The goal is to find the root of f(x) in the interval [0, 2pi]

I'm using the program GeoGebra to get the task done of finding the roots. In this case, there are 2 roots and they are marked by the points A and B in the attachment shown

A = (1.91, 0)
B = (4.37, 0)

So the two solutions for theta are
theta = 1.91 radians
theta = 4.37 radians

8 0
3 years ago
members of the wide waters club pay 105 dollars per summer season, plus 9.50 each time they rent a boat. Nonmembers must pay 14.
WITCHER [35]
When handling problems of this nature make sure you setup the equations. 
x = number of times they rent a boat. 

Members 
Cost = 105 + 9.50x
Non members because members don't have to pay the 105 we leave it out. 
Cost = 14.75x 

so now to determin when cost would be equal we set the two equations = to each other

105 + 9.50x = 14.75x 

now solve for x 

105 = 5.25x
 
20 = x 

so they would have to rent 20 times to equal each other. 
4 0
3 years ago
How do I solve the Question​
Mandarinka [93]

Answer:

subtract 200

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
If f(x) = 4x2 - 5x + 7 and g(x) = 3x2 - 2x + 8, find f(x) + g(x). A) 7x2 - 7x + 15 B) 7x4 - 7x2 + 15 C) 7x2 + 15 D) 12x4 - 8x3 +
lutik1710 [3]

Answer:

A) 7x^2-7x+15

Step-by-step explanation:

f(x) = 4x2 - 5x + 7,

g(x) = 3x2 - 2x + 8

f(x) +g(x) =

4x^2 - 5x + 7 + 3x^2 - 2x + 8=

7x^2-7x+15

8 0
3 years ago
Which statement is true? Select all that apply.
julsineya [31]
It’s b and c and i believe a
3 0
2 years ago
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