A green ribbon is 9 inches long. A red ribbon is 1/10 the length of the green

Rosie has £m in her pocket she is given £4 pocket money write an expression for how much money she has now

aksik [14]

Answer:

m+4

Step-by-step explanation:

She currently has a variable "m" in her pocket which we don't know, BUT we know how much she is getting, which is 4.

3 0

3 years ago

Verify that your point from Question 2 is a solution to 2x-y=-12x−y=−1 AND is also a solution to y=5x-5y=5x−5. What does it mean

Vera_Pavlovna [14]

Answer:

(a) Verified

(b) They are simultaneous equations

Step-by-step explanation:

Given

$2x - y = -1$

$y =5x - 5$

Required

Verify that: $(x,y) = (2,5)$ is a solution

We have:

$2x - y = -1$

Substitute: $(x,y) = (2,5)$

$2 * 2 - 5 = -1$

Evaluate all products

$4 - 5 = -1$

Subtract:

$-1 = -1$

Because both sides of the equation are equal, then the point is a solution

Also: $y =5x - 5$

Substitute: $(x,y) = (2,5)$

$5 = 5 * 2 - 5$

Evaluate all products

$5 = 10 - 5$

Subtract:

$5 = 5$

Because both sides of the equation are equal, then the point is a solution

Because the given point is a solution to both equations, then they are simultaneous equation

7 0

3 years ago

Which polynomial is represented by the algebra tiles?

aev [14]

Answer:

2x^2-4x-6

Step-by-step explanation:

I don't know what kind of math this is, but simply add up all of the like-terms.

There are 2 +x^2 --> 2x^2

There are 4 -x --> -4x

There are 6 - --> -6

7 0

3 years ago

Read 2 more answers

Click this and your gay lolol

almond37 [142]

Answer:

gay.... for points

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Compilers can have a profound impact on the performance of an application. Assume that for a program, compiler A results in a dy

mixas84 [53]

Incomplete question as we have not told what to find.So I have assumed to find average CPI for each program.So complete question is here

Compilers can have a profound impact on the performance of an application. Assume that for a program, compiler A results in a dynamic instruction count of 1.0E9 and has an execution time of 1.1 s, while compiler B results in a dynamic instruction count of 1.2E9 and an execution time of 1.5 s.

Find the average CPI for each program given that the processor has a clock cycle time of 1 ns.

Answer:

$CPI_{A}=1$

$CPI_{B}=1.25$

Step-by-step explanation:

As we know CPU time given as

$CPU_{time}=instructions*CPI*Cycle_{time} \\So\\CPI=\frac{CPU_{time}}{instructions*Cycle_{time}}\\ Where\\Cycle_{time}=1*10^{-9}s\\ And\\executionTime=CPUtime$

For Compiler A

$CPI_{A}=\frac{CPU_{timeA} }{instruction_{A}*Cycle_{time} }\\CPI_{A}=\frac{1s}{10^{9}*1.0*10^{-9}s }\\CPI_{A}=1$

For Compiler B

$CPI_{B}=\frac{CPU_{timeB} }{instruction_{B}*Cycle_{timeB} }\\CPI_{B}=\frac{1.5s}{(1.2*10^{9})*(1.0*10^{-9}s) }\\CPI_{B}=1.25$

8 0

3 years ago