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3 years ago

Simplify the following rational expression

Mathematics

2 answers:

madreJ [45]3 years ago

8 0

Step-by-step explanation:

as the denominator (x+3) is in both you need only one denominator to be multiplied in first rational number .

2x (x-2). + 5.

(x+3) (x-2). (x+3) (x-2)

2x^2-4x +5

(x+3) (x-2)

it's cannot be solved after that.

mariarad [96]3 years ago

7 0

Answer: The simplified expression is

(2x² + x + 15)/(x + 3)(x - 2)

Step-by-step explanation:

The given expression is

2x/(x+ 3) + 5/(x + 3)(x - 2)

Looking at the denominator, the Lowest common factor is (x + 3)(x - 2). Multiplying through by (x + 3)(x - 2), it becomes

[2x(x - 2) + 5(x + 3)]/(x + 3)(x - 2)

We would simplify by applying the distributive property. Each term inside the bracket is multiplied by each term outside the bracket. It becomes

[2x² - 4x + 5x + 15)]/(x + 3)(x - 2)

= (2x² + x + 15)/(x + 3)(x - 2)

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1. Which point on the axis satisfies the inequality y

grigory [225]

Answer:

1) Point $(1,0)$ -----> see the attached figure N $1$

2) The value of x is $4$

3) I quadrant

4) $(1,1)$

5) $y>-5x+3$

Step-by-step explanation:

Part 1)

we know that

If the point satisfy the inequality

then

the point must be included in the shaded area

The point $(1,0)$ is included in the shaded area

Part 2)

we have

$x-2y\geq 4$

see the attached figure N $2$

we know that

The value for x on the boundary line and the x axis is equal to the x-intercept of the line $x-2y= 4$

For $y=0$

Find the value of x

$x-2(0)= 4$

$x=4$

The solution is $x=4$

Part 3)

we have

$x\geq 0$ -----> inequality A

The solution of the inequality A is in the first and fourth quadrant

$y\geq 0$ -----> inequality B

The solution of the inequality B is in the first and second quadrant

the solution of the inequality A and the inequality B is the first quadrant

Part 4) Which ordered pair is a solution of the inequality?

we have

$y\geq 4x-5$

we know that

If a ordered pair is a solution of the inequality

then

the ordered pair must be satisfy the inequality

we're going to verify all the cases

case A) point $(3,4)$

Substitute the value of x and y in the inequality

$x=3,y=4$

$4\geq 4(3)-5$

$4\geq 7$ ------> is not true

therefore

the point $(3,4)$ is not a solution of the inequality

case B) point $(2,1)$

Substitute the value of x and y in the inequality

$x=2,y=1$

$1\geq 4(2)-5$

$1\geq 3$ ------> is not true

therefore

the point $(2,1)$ is not a solution of the inequality

case C) point $(3,0)$

Substitute the value of x and y in the inequality

$x=3,y=0$

$0\geq 4(3)-5$

$0\geq 7$ ------> is not true

therefore

the point $(3,0)$ is not a solution of the inequality

case D) point $(1,1)$

Substitute the value of x and y in the inequality

$x=1,y=1$

$1\geq 4(1)-5$

$1\geq -1$ ------> is true

therefore

the point $(1,1)$ is a solution of the inequality

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we know that

The equation of the line has a negative slope

The y-intercept is the point $(3,0)$

The x-intercept is a positive number

The solution is the shaded area above the dashed line

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