<img src="https://tex.z-dn.net/?f=f%28x%29%3D3%20x%5E%7B2%7D%20%2B12x%2B16" id="TexFormula1" title="f(x)=3 x^{2} +12x+16" alt="f

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ira [324]

3 years ago

(x)=3 x^{2} +12x+16" align="absmiddle" class="latex-formula"> find the minimum. show work

Mathematics

1 answer:

Sunny_sXe [5.5K]3 years ago

4 0

$f$ =3x $x^2$ +12x+16 divided by $x$

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Evaluate the surface integral:S

rjkz [21]

Assuming $S$ does not include the plane $z=0$ , we can parameterize the region in spherical coordinates using

$\mathbf r(u,v)=\left\langle3\cos u\sin v,3\sin u\sin v,3\cos v\right\rangle$

where $0\le u\le2\pi$ and $0\le v\le\dfrac\pi/2$ . We then have

$x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v$
$(x^2+y^2)=9\sin^2v(3\cos v)=27\sin^2v\cos v$

Then the surface integral is equivalent to

$\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du$

We have

$\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle$
$\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle3\cos u\cos v,3\sin u\cos v,-3\sin v\rangle$
$\implies\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle-9\cos u\sin^2v,-9\sin u\sin^2v,-9\cos v\sin v\rangle$
$\implies\left\|\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}\|=9\sin v$

So the surface integral is equivalent to

$\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du$
$=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv$
$=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw$

where $w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv$ .

$=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}$
$=\dfrac{243}2\pi$

4 0

3 years ago

The dimensions of a rectangle can be given by x+7 and x+2. If the area of the rectangle is 66 square inches, what are the dimens

Nadusha1986 [10]

to solve for the dimensions (x+7)(x+2)=66,

we can first use the foiling method to simplify the left side.

x^2 + 2x + 7x + 14 = 66

x^2 + 9x + 14 = 66

now, subtract 66 from both sides.

x^2 + 9x - 52 = 0

now, split this into two parentheses.

(x + 13)(x - 4)

since the root of -13 would give you negative values, x=4. This means that the dimensions of the rectangle are 11 and 6.

7 0

3 years ago

There are 4 consecutive integers that have a sum of 18. What is the value of the least<br> integer?

EleoNora [17]

3,4,5,6

The lowest integer is 3

4 0

2 years ago

One leg of a right triangle has a length of 5m. The other sides have lengths that are consecutive integers. Find these lengths.

pickupchik [31]

The lengths of the other two sides of the right triangle are 12 and 13

<h3>Pythagorean theorem </h3>

From the question, we are to determine the lengths of the other sides of the triangle

From the given information,

The other sides have lengths that are consecutive integers

Thus,

If the length of the other side is x

Then,

The hypotenuse will be x + 1

By the <em>Pythagorean theorem</em>, we can write that

(x+1)² = x² + 5²

(x+1)(x+1) = x² + 25

x² + x + x + 1 = x² + 25

x² - x² + x + x = 25 - 1

2x = 24

x = 24/2

x = 12

∴ The other leg of the right triangle is 12

Hypotenuse = x + 1 = 12 + 1 = 13

Hence, the lengths of the other two sides are 12 and 13

Learn more on Pythagorean theorem here: brainly.com/question/4584452

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2 years ago

2(5x+4)-3x<br>Only for Best users.

OlgaM077 [116]

Answer:

7x+8

Step-by-step explanation:

2(5x+4)-3x

distribute: 10x+8-3x

=7x+8

6 0

3 years ago

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