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Whitepunk [10]
3 years ago
7

Explain why the initial value of any function of the form f(x) = a(bx) is equal to a.

Mathematics
1 answer:
Montano1993 [528]3 years ago
7 0
So the said problem asking to explain or justify why the initial value of any function of the form f(x) = a(bx) is equal to a. For me I won't agree with the said question, the said function is determine through the value of X because it is the undefined value in the equation that is needed to be define. I hope this would help 
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Find the equation of the line that is perpendicular to y = –2x + 5 and contains the point
ivann1987 [24]

The given equation is: y+2x=5

To find the line perpendicular to it, we interchange coefficients and switch the signs of one coefficient.

The equation to a line perpendicular to it is:

$ 2y-x=c$

where, $c$ is some constant we have determine using the condition given.

It passes through $(2,-1)$

Put the point in our equation:

$2(-1)-(2)=c$

$c=-2-2$

$c=-4$

The final equation is:

$\boxed{ 2y-x=-4}$

4 0
3 years ago
How do you do this TwT
tangare [24]

Answer:

Step-by-step explanation:

First step plug the numbers into the equation.

-10/(5+2) = (-10/5) + (-10/2)

Solve both sides of the equation separately.

-10/(5+2) Use distributive property, multiply both 5 and 2 by -10.

= -50 + (-20) = -70

-10/5 + -10/2 Multiply the fractions so they can be added together.

-10/5*2 = -20/10  -10/2*5 = -50/10

-20/10 + -50/10 = -70

Now you have solved both equations and they are both equal to -70, so you have verified that the equations are equal to each other because they both equal -70.

5 0
2 years ago
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