Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
Answer:
You compare it by this
Step-by-step explanation:
Linear functions are graphed as straight lines while exponential functions are curved. Linear functions are typically in the form y = mx + b, which is used to discover the slope, or simply the change in y divided by the change in x, while exponential functions are typically in the form y = (1 + r) x.
H'(x) = 2f'(x)
h'(1) = 2*f'(1) = 2*4
h'(1) = 8
So it's 2.40 subtract 2, which is 0.4
then put it over 2, you get 0.4/2, which is equal to 0.2
0.2= 20% so it's 20% of increase
It is...........
2.789=2 ones and 7 tenths 8 hundreths 9 thousandths
