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3 years ago

8

85x71 Estimate products

1 answer:

Nikolay [14]3 years ago

6 0

Answer:

6000

Step-by-step explanation:

85 x 71 would be 6035

then estimate it, you get 6000

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PLEASE HELP! Urgent!!!

zaharov [31]

Answer:

$\frac{9}{2}\pi +35$

Step-by-step explanation:

The area of trapezoid is given by the formula:

$A=\frac{1}{2}(b_1+b_2)h$

Where

A is the area

b_1 is base 1

b_2 is base 2, and

h is the height

Looking at the figure, base 1 is the left line which goes from y = 3 to y = 3, so 6 units. Also, base 2 is the right line which goes from y = -3 to y =5, so 8 units.

The height is the horizontal distance in the middle, which goes from x = -2 to x = 3, so 5 units. Hence area of trapezoid is:

$A=\frac{1}{2}(b_1+b_2)h\\A=\frac{1}{2}(6+8)*5\\A=35$

Now, area of semicircle is:

$A=\frac{\pi r^2}{2}$

Where

A is the area

r is the radius

Looking at the figure, the diameter (twice radius) goes from y = -3 to y = 3, so 6 units. But radius is half of that, so 3 units. Hence area of semicircle is:

$A=\frac{\pi r^2}{2}\\A=\frac{\pi (3)^2}{2}\\A=\frac{9}{2} \pi$

Total area of the figure is $\frac{9}{2}\pi +35$

4 0

4 years ago

I'LL NAME YOU BRAINIEST!!!! Find the equation for the line which contains the points (0, -3) and (14, 0). Express your answer in

vova2212 [387]

It’s 5+3x 10-1= 21345

5 0

4 years ago

Helpppppppppppppppppppp

alisha [4.7K]

Answer:

6:5:4

Step-by-step explanation:

6 + 5 + 4 = 15

3000/15 = 200

200 x 6 = 1200 = eldest

200 x 5 = 1000 = 2nd eldest

1200 + 1000 = 2200

3000 - 2200 = 800

200 x 4 = 800 = youngest

6 0

3 years ago

Read 2 more answers

Two corporate baseball teams are scheduled to play a game together. They agree that if both teams attend or if neither team atte

sp2606 [1]

Answer:

2.99% probability that the cost will be paid by only one team

Step-by-step explanation:

The binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability that a team plays:

A team plays if it has at most 2 injured players out of 11.

11 players, so $n = 11$

Each player with a 5% probability of injury, so $p = 0.05$

Then

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{11,0}.(0.05)^{0}.(0.95)^{11} = 0.5688$

$P(X = 1) = C_{11,1}.(0.05)^{1}.(0.95)^{10} = 0.3293$

$P(X = 2) = C_{11,2}.(0.05)^{2}.(0.95)^{9} = 0.0867$

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.5688 + 0.3293 + 0.0867 = 0.9848$

Each team has a 0.9848 probability of showing up to play.

What is the probability that the cost will be paid by only one team?

This happens if one team shows up and the other do not.

2 teams, so $n = 2$

Each team has a 0.9848 probability of showing up to play, so $p = 0.9848$ .

This probability is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{2,1}.(0.9848)^{1}.(0.0152)^{1} = 0.0299$

2.99% probability that the cost will be paid by only one team

7 0

4 years ago

Need po answer plssss

Ede4ka [16]

Answer:

owshhittttttt mic drop️

7 0

3 years ago