Answer: I would think 4 because there are plants every were there like literally there is lots of flowers green bushes trees vines there's lots of wonderful beautiful stuff there so I think the number 4
Explanation:
A rainforest orchid. Orchids are very common plants in the tropical rainforest. The Amazon Rainforest itself is home to more than 40,000 plant species! The most common tree in the Amazon Rainforest is the açai here are some of the plants there are there
Bromeliads Plant (Bromeliaceae)
Emergent Plant
Heliconia Flower (Lobster-Claw)
Orchid Plant
Passion flowers (Passiflora spp.)
Lianas
Vines
Rubber Tree (Hevea brasiliensis)
Cacao (Theobroma cacao)
Giant Water Lilies (Victoria amazonica)
Answer:The structure of solids can be described as if they were three-dimensional analogs of a piece of wallpaper. Wallpaper has a regular repeating design that extends from one edge to the other. Crystals have a similar repeating design, but in this case the design extends in three dimensions from one edge of the solid to the other.
We can unambiguously describe a piece of wallpaper by specifying the size, shape, and contents of the simplest repeating unit in the design. We can describe a three-dimensional crystal by specifying the size, shape, and contents of the simplest repeating unit and the way these repeating units stack to form the crystal.
The simplest repeating unit in a crystal is called a unit cell. Each unit cell is defined in terms of lattice points--the points in space about which the particles are free to vibrate in a crystal.
First, it is best to know the chemical formula of pyridine which is C5H5N. To determine the number of carbon atoms present in pyridine, multiply 7.05 mol C5H5N with 5 mol C/ 1 mol C5H5N which then results to 35.35 mol of carbon. Then, multiply the answer to Avogadro's number which is 6.022x10^23 atoms. It is then calculated that the number of carbon atoms in 7.05 moles of pyridine is 2.12x10^25 atoms.
Acid is 1. a substance that increases the hydrogen ion concentration of a solution
<span>2. removes hydroxide ions because of the tendency for H+ to combine with OH-</span>
3 covalent bonds (there are 2 electrons in the first orbital and 5 in the second. You still have room for three more)