Answer:
128g
Explanation:
Given parameters:
Mass of carbon = 48g
Mass of carbon dioxide = 176g
Unknown:
Mass of oxygen that reacted = ?
Solution:
Every chemical reaction must obey the law of conservation of mass. It states that "in a chemical reaction, matter is neither created nor destroyed" .
So;
Mass of carbon + Mass of oxygen = Mass of carbon dioxide
Mass of oxygen = Mass of carbon dioxide - Mass of carbon
Mass of oxygen = 176 - 48 = 128g
Substitution Reactions are those reactions in which one nucleophile replaces another nucleophile present on a substrate. These reactions can take place via two different mechanism i.e SN¹ or SN². In SN¹ substitution reactions the leaving group leaves first forming a carbocation and nucleophile attacks carbocation in the second step. While in SN² reactions the addition of Nucleophile and leaving of leaving group take place simultaneously.
Example:
OH⁻ + CH₃-Br → CH₃-OH + Br⁻
In above reaction,
OH⁻ = Incoming Nucleophile
CH₃-Br = Substrate
CH₃-OH = Product
Br⁻ = Leaving group
Organic reactions are typically slower than ionic reactions because in organic compounds the covalent bonds are first broken, this breaking of bonds is a slower step, while, in ionic compounds no bond breakage is required as it consists of ions, so only bond formation takes place which is a quicker and fast step.
Answer:
1) 950 mL
2) 625 mmHg
3) 426 mL
Explanation:
1) This is the relationship between pressure and volume. This relationship looks like this:
P1*V1 = P2*V2
This means the first pressure times the initial volume is equal to the second pressure times the second volume. We are solving for the second volume. First, convert the mmHg to atm and the mL to L.
1 L * 1 atm = 1.053 atm * X
X = 0.95 L or 950 mL
2) This is the same concept as the last one. :) We don't have to convert the mmHg to atm since the answer wants it in mmHg.
750 mmHg * 0.25 L = 0.3 L * X
X = 625 mmHg
3) The relationship between volume and temperature is similar to the one between pressure and temperature (like the problem in your last question). Remember to convert degrees C to Kelvin and mL to L.
V1 / T1 = V2 / T2
0.4 L / 303 K = X / 323 K
X = 0.426 L pr 426 mL
These problems become much easier once you learn the relationships between the different variables (temp, pressure, volume, etc.) When you have a problem like this, I like to first determine what relationship I am dealing with and then write out what I have and what I am solving for. This helps with organizing the problem. Then just solve it like a normal algebra problem. Always remember to convert temp to Kelvin, mL to L, and pressure to atm (unless it wants it in a different unit, then just make sure all the units match).
Good luck with you studies! :)
<u>We are given:</u>
The force applied on the poor hamster (F) = 12 N
Acceleration of the poor Hamster (a) = 8 m/s²
<u>Solving for the mass of the Poor Hamster:</u>
From newton's second equation of motion, we know that:
F = ma
<em>replacing the given values</em>
12 = 8 * m
m = 12/8 kg
m = 3/2 kg
The poor Hamster weighs 3/2 kg
Tempratures
1. -60 C = 213.15 K
2. 250 C= 523.15 K
3. 365 K = 91.85 C
4. 205 K = -68.15 C
Pressures
1. 22.0 inches Hg = 558.8 mm Hg
2. 3.4 atm = 2584 mm Hg
3. 680 mm Hg = 0.894737 atm
4. 785 mm Hg = 104.658 kPa
Hope this helped! Please mark as brainliest! Thanks!
Although It showes I'm a begginer, I was An Ace, till my account got deleted.
My name was Sorry14.
