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Serhud [2]
3 years ago
14

What is the pH of a solution of H2SO4 that has [H3O+] = 5.45 × 10–5 M?

Chemistry
2 answers:
marshall27 [118]3 years ago
8 0

the correct answer is 4.26

Katena32 [7]3 years ago
5 0
In chemistry, pH<span> is a numeric scale used to specify the acidity or basicity of an aqueous solution. It is approximately the negative of the base 10 logarithm of the concentration of hydronium ions. We calculate as follows:

pH = -log [H3O+]
pH = -log[</span><span>5.45 × 10–5 M]
pH = 4.3</span>
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What are some examples of gases at room temperature
Lady_Fox [76]

Answer:

Nitrogen, Hydrogen, Oxygen, Chlorine, and Fluorine are all gases at room temperature.

Explanation:

6 0
3 years ago
What is precipitation in formation of salts?​
seraphim [82]

Answer:A precipitation reaction refers to the formation of an insoluble salt when two solutions containing soluble salts are combined. The insoluble salt that falls out of solution is known as the precipitate, hence the reaction's name. Precipitation reactions can help determine the presence of various ions in solution.

Explanation:

4 0
2 years ago
Consider the equation:
Dmitry [639]

Answer:1. Rate=k[CHCl_3]^1[Cl_2]^\frac{1}{2}

2. The rate constant (k) for the reaction is 3.50M^\frac{-1}{2}s^{-1}

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

rate=k[CHCl_3]^x[Cl_2]^y

k= rate constant

x = order with respect to CHCl_3

y = order with respect to Cl_2

n = x+y= Total order

1. a) From trial 1: 0.0035=k[0.010]^x[0.010]^y  (1)

From trial 2: 0.0069=k[0.020]^x[0.010]^y   (2)

Dividing 2 by 1 :\frac{0.0069}{0.035}=\frac{k[0.020]^x[0.010]^y}{k[0.010]^x[0.010]^y}

2=2^x,2^1=2^x therefore x=1.

b)  From trial 2: 0.0069=k[0.020]^x[0.010]^y   (3)

From trial 3: 0.0098=k[0.020]^x[0.020]^y   (4)

Dividing 4 by 3:\frac{0.0098}{0.0069}=\frac{k[0.020]^x[0.020]^y}{k[0.020]^x[0.010]^y}

1.4=2^y,2^{\frac{1}{2}}=2^y therefore y=\frac{1}{2}

rate=k[CHCl_3]^1[Cl_2]^\frac{1}{2}

2. to find rate constant using trial 1:

0.0035=k[0.010]^1[0.010]^\frac{1}{2}  

k=3.50M^\frac{-1}{2}s^{-1}

5 0
3 years ago
The probability of finding electrons in certain regions of an atom is described by?
inysia [295]

Answer:

orbits

Explanation:

An orbital is a region of space where there is a high probability of finding an electron.

5 0
3 years ago
A compound contains 40 g of calcium, 12 g of carbon, and 48 g of oxygen. What is its empirical formula
Deffense [45]

Answer:

CaCO3

Explanation:

answer attached

hope this helps!

5 0
2 years ago
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