2x² - 128
2(x² - 64), but (x² - 64) = x² - 8² (difference of 2 squares),[a²-b²=(a-b)(a+b)]
2(x² - 64) = 2(x² - 8²) = 2(x-8)(x+8)
Answer:
2 sqrt(2x-1)
Step-by-step explanation:
f(x) = sqrt( x+9)
g(x) = 8x-13
f(g(x))
place the function g(x) in for x in f(x)
f(g(x)) = sqrt(8x-13+9)
Combine like terms
f(g(x)) = sqrt(8x-4)
Factor out 4
f(g(x)) = sqrt(4*(2x-1)
2 sqrt(2x-1)
Answer:
1968
Step-by-step explanation:
A= basexheight
= 48x41
= 1968
Units: If base and height are given in metres, units of area will be m².
If they are in cm, them unit of area= cm².
a+b+c=0
[(a+b+c)^2=a^2+b^2+c^2+2ab+2ac+2bc]
[a^2+b^2+c^2+2ab+2ac+2bc=0]
[a^2+b^2+c^2=-(2ab+2ac+2bc)]
[a^2+b^2+c^2=-2(ab+ac+bc)] (i)
also
[a=-b-c]
[a^2=-ab-ac] (ii)
[-c=a+b]
[-bc=ab+b^2] (iii)
adding (ii) and (iii) ,we have
[a^2-bc=b^2-ac] (iv)
devide (i) by (iv)
[(a^2+b^2+c^2)/(a^2-bc)=(-2(ab+bc+ca))/(b^2-ac)]
