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2 years ago

If a position on the ocean floor is 12 kilometers below the sea level, which value describes the elevation of the ocean floor

Mathematics

1 answer:

LenKa [72]2 years ago

4 0

Answer:

- 12

Step-by-step explanation:

The sea level serves as a reference point and may be used to describe objacetsvir positions above or below it. Therefore, the sea level is regarded as a zero point or level. Hence, objects below are describes to be at a negative distance while those above are assigned the positive sign. Hence, for a position which is 12 km below sea level, then the object is said to be at a distance of - 12 km (below sea level takes the negative sign.)

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RUDIKE [14]

Answer: See explanation

Step-by-step explanation:

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2 years ago

Solve 9^x + 4 = 11 for x using the change of base formula log base b of y equals log y over log b.

Sauron [17]

Answer:

If you meant $9^x+4=11$ , then the answer is approximately 0.866.

If you meant $9^{x+4}=11$ , then the answer is approximately -2.909 which looks like what you meant based on the choices.

Step-by-step explanation:

$9^x+4=11$

First step is to get the exponential part by itself. The part that has the variable exponent which is the $9^x$ term.

To do this we need to subtract 4 on both sides:

$9^x=11-4$

Simplify:

$9^x=7$

The equivalent logarithmic form is:

$\log_9(7)=x$

I always say to myself the logarithm is the exponent that is how I know what to put opposite the side containing the log.

Anyways if you don't have options for computing $\log_b(a)$ in your calculator you need to use the change of base formula.

$\frac{\log(7)}{\log(9)}=x$

So $x \approx 0.8856$

I don't see this as a choice so maybe you actually meant the following equation:

$9^{x+4}=11$

Let's see if this is the correct interpretation.

So the exponential part is already isolated.

So we just need to put in the equivalent logarithmic form:

$\log_9(11)=x+4$

Now we subtract 4 on both sides:

$\log_9(11)-4=x$

Again if you don't have the option for computing $\log_b(a)$ in your calculator, you will have to use the change of base formula:

$\frac{\log(11)}{\log(9)}-4=x$

$x \approx -2.909$

6 0

2 years ago

Solve 5x - c = k for x<br><br> Answers above

Rama09 [41]

Answer:

x = ( k+c)/5

Step-by-step explanation:

5x - c = k

Add c to each side

5x -c+c = k+c

5x = k+c

Divide by 5

5x/5= ( k+c)/5

x = ( k+c)/5

5 0

3 years ago

Read 2 more answers

Simplify the expression. 8x^-10 y^'6 -2x^2y^-8 Write your answer without negative exponents.

sergij07 [2.7K]

Answer:

$8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^{14} - 2x^{12}}{x^{10}y^8}$

Step-by-step explanation:

Given

$8x^{-10}y^6 - 2x^2y^{-8}$

Required

Simplify

Rewrite as:

$8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^6}{x^{10}} - \frac{2x^2}{y^8}$

Take LCM

$8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^6*y^8 - 2x^2 * x^{10}}{x^{10}y^8}$

Apply law of indices

$8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^{14} - 2x^{12}}{x^{10}y^8}$

8 0

2 years ago

According to the National Institute on Drug Abuse, a U.S. government agency, 17.3% of 8th graders in 2010 had used marijuana at

miskamm [114]

Answer:

The conditions for use of the normal model to represent the distribution of sample proportion are not met. He should increase the sample size until the conditions are met.

If the test is done anyway, the null hypothesis failed to be rejected.

The conclusion is taht there is not enough evidence to support the claim that the percentage is lower in this district.

Step-by-step explanation:

The conditions for use of the normal model to represent the distribution of sample proportion are not met, as the affirmative responses are less than 10.

$np=80*0.1=8$

If the test of hypothesis is done as if the conditiones were met, we know that the claim is that the percentage is lower in this district.

Then, the null and alternative hypothesis are:

$H_0: \pi=0.173\\\\H_a:\pi$

The significance level is 0.05.

The sample has a size n=80.

The sample proportion is p=0.1.

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.173*0.827}{80}}\\\\\\ \sigma_p=\sqrt{0.001788}=0.042$

Then, we can calculate the z-statistic as:

$z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.1-0.173+0.5/80}{0.042}=\dfrac{-0.067}{0.042}=-1.578$

This test is a left-tailed test, so the P-value for this test is calculated as:

$P-value=P(z$

As the P-value (0.057) is greater than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the percentage is lower in this district.

7 0

2 years ago