No.
a. take 35% off 30 =19.5
b. first take 25% off 30 = 22.5, then take 10% off 22.5 = 20.25
Answer: 12 sqrt(5)
Explanation:
First simplify:
= Sqrt(45)
= sqrt(9*5) sqrt of 9 is 3 so bring out 3
= 3sqrt(5)
= 2sqrt(20)
= 2sqrt(4*5) sqrt of 4 is 2 so bring that out and multiply it by 2
= 4sqrt(5)
= 5 sqrt(5) is already simplified
= 3sqrt(5) + 4 sqrt(5) + 5sqrt(5)
= 12 sqrt(5)
Answer:
a.) Between 0.5 and 3 seconds.
Step-by-step explanation:
So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.
If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.
Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.
So, the answer is a.) between 0.5 and 3 seconds.