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3 years ago

PLEASE ANSWER ASAP!!!! MUST BE CORRECT FOR POINTS GIVEN!!!!! THE QUESTION IS BELOW IN THE SCREENSHOT!!!!! VERY IMPORTANT!!!!!

Mathematics

2 answers:

olchik [2.2K]3 years ago

8 0

A and D . That was an easy one. Good luck!

Nady [450]3 years ago

7 0

A and D because x is 1/3y not 3y and x times y would be 48 and yes I'm sure

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Divide by 2 to get 1/3 of the week:

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1/8 x 3 = 3/8

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3 years ago

The difference of n and 7 is no more than 12. Find all possible values of n.

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-5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29

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either one is acceptable. question was not clear but i did my best! :)

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Use each model to predict the life expectancy of residents of a country for which the average annual income is $80,000

Mandarinka [93]

The life expectancies of residents of a country for which the average annual income is $80,000 for the three models are 12309.9352, 172.2436 and 4828.1393

The life expectancies of the models are given as:

$y =69.9352 + 0.1530\times (income)$ --- model 1

$y =4.2436 + 0.0021\times (income)$ --- model 2

$y =4.1393 + 0.0603\times (income)$ --- model 3

Given that the average annual income is $80,000;

We simply substitute 80000 for income in the equations of the three models.

So, we have:

Model 1

$y =69.9352 + 0.1530\times (income)$

$y =69.9352 + 0.1530\times 80000$

$y =12309.9352$

Model 2

$y =4.2436 + 0.0021\times (income)$

$y =4.2436 + 0.0021\times 80000$

$y =172.2436$

Model 3

$y =4.1393 + 0.0603\times (income)$

$y =4.1393 + 0.0603\times 80000$

$y =4828.1393$

Hence, the life expectancies are 12309.9352, 172.2436 and 4828.1393