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lbvjy [14]
3 years ago
15

The precipitating factor for a dissociative episode is usually a(an) _____ episode of hallucinogen use. injury with loss of cons

ciousness. sudden deficiency in serotonin. unbearable stress.
Biology
1 answer:
LUCKY_DIMON [66]3 years ago
3 0

Answer – Unbearable Stress

 

The precipitating factor for a dissociative episode is usually an unbearable stress. While heavy use of alcohol, history of head trauma, epilepsy, and major depressive disorder (MDD) have all been associated with dissociative fugue, i<span>ts onset is usually associated with a stressful life event.</span>

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EPA scientists performed an experiment where coal was
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2 years ago
You are a botanist looking at the plant color in a new breed of Snapdragon. The two parent plants are Blue and Green and when yo
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Incomplete dominance is the inheritance pattern where the dominant allele did not mask the recessive allele completely and form a mix of both alleles. Here the inheritance is the incomplete inheritance. The ratio of F2 generation is 1:2:1.

Given:

R1R1 = 42

R2R2 = 39

R1R2 = 86

Total R1 alleles = 2*42+86 = 170

Total R2 alleles = 2*39+86 = 164

Total alleles = 334

Frequency of allele R1 = 170/334 = 0.51

Frequency of allele R2 = 164 / 334 = 0.49

Expected number of each phenotype:

Total population = 167

Blue = R1R1 = 0.51 * 0.51 * 167 = 43.44

Green = R2R2 = 0.49 * 0.49 * 167 = 40.10

Cyan = 2*R1*R2 = 2*0.51*0.49*167 = 83.46

Phenotype     Observed(O)    Expected (E)    O-E      (O-E)2     (O-E)2/E

Blue                 42                   43.44               -1.44       2.0736     0.0477

cyan                86                   83.46                 2.54     6.4516     0.0773

green              39                    40.1                    -1.1       1.2100      0.0302

Total              167                     167                                               0.1552

Chi-square value = 0.155

Degrees of freedom = no. of phenotypes – 1

Df = 3-1 = 2

Critical value = 5.99

Chi-square value of 0.155 is less than the critical value of 5.99. So we accept the null hypothesis.

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