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2 years ago

Divide 7/5 by 3/5 A.7/9 B.75/21 C.7/25 D.21/75

1 answer:

7 0

ok turn 7/5 and 3/5 into a decimal
here let me help you

3/5 = 0.6
7/5 = 1.4

1.4 / 0.6 = 2.3 repeat

then turn it back into a fraction which is 2 3/10

this is how I do it by the way.

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Find the value of y for the given value of x. Round to the nearest hundredth. y = 15 + 3 ln x; x = 7.2

Nikolay [14]

Answer:

y = 20.922

Step-by-step explanation:

Simply plug in <em>x</em> and evaluate:

y = 15 + 3ln(7.2)

Only way to calculate ln is to plug into a calc:

We should get 20.9222 as our answer.

7 0

3 years ago

Find the LCM ( least common multiple ) of 8, 12, and 16.

abruzzese [7]

the answer for find the lcm of 8,12 and 16 is answer a.48

6 0

3 years ago

Read 2 more answers

Please help please help please help

uranmaximum [27]

It should be 986m

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2(17x17)= 578

408+578=986

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2 years ago

When dividing the polynomial using synthetic division, which of the following setup boxes would be used?

Galina-37 [17]

The setup boxes in the synthetic division are (b)

<h3>How to determine the setup boxes?</h3>

The dividend is given as:

x^3 + 4x^2 + x - 6

The divisor is given as:

x - 2

Set the divisor to 0

x - 2 = 0

Solve for x

x = 2

Remove the variables in the dividend

1 + 4 + 1 - 6

Remove the arithmetic signs

1 4 1 - 6

So, the setup is:

2 | 1 4 1 - 6

Hence, the setup boxes are (b)

Read more about synthetic division at:

brainly.com/question/12951962

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8 0

1 year ago

Find the length x to the nearest whole number. A right triangle has a vertical leg of length x units, a base leg with a length o

wel

Complete Question

The diagram for this question is shown on the first uploaded image

Answer:

The value of x is $x = 274 \ unites$

Step-by-step explanation:

From the question we are told that

The length of the vertical length is $x$

The length of the base leg is L = 330 + d units

The length of the bisecting line segment is h

The base angle is $\theta = 28^o$

The angle between d and line segment is $\theta_1 = 56^o$

For the first angle

$Tan \theta_1 = \frac{x}{d}$

=> $d = \frac{x}{Tan \theta _1}$

For the whole big triangle

$Tan \theta = \frac{x}{330 + d}$

=> $d = \frac{x}{Tan \theta } -330$

So equating the both d

$\frac{x}{Tan \theta _1} = \frac{x}{Tan \theta } -330$

Substitute values

$\frac{x}{Tan (56)} = \frac{x}{Tan (28) } -330$

$0.6745 x = 1.880x -330$

$1.20549 x = 330$

$x = 274 \ unites$

5 0

2 years ago